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Pick out the incorrect statement about C...

Pick out the incorrect statement about CO .

A

In laboratory it is prepared by dehydrating HCOOH with conc. `H_2SO_4`

B

CO is neutral oxide and acts as a fuel

C

It reduces aqueous solution of `PdCl_2` to metallic Pd

D

Co forms complex with haemoglobin and this complex is less stable than oxyhaemoglobin

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AI Generated Solution

The correct Answer is:
To determine the incorrect statement about carbon monoxide (CO), we will analyze each of the provided statements step by step. ### Step 1: Analyze the first statement **Statement:** In the laboratory, CO can be prepared by dehydrating formic acid (HCOOH) with H2SO4. - **Explanation:** This statement is true. When formic acid is treated with sulfuric acid (H2SO4), which acts as a dehydrating agent, water is removed, leading to the formation of carbon monoxide (CO) and other byproducts. ### Step 2: Analyze the second statement **Statement:** Cu is a neutral oxide. - **Explanation:** This statement is also true. Copper (Cu) can be considered a neutral oxide because it does not react with acids or bases in a significant manner, and it can be used in various applications, including as a fuel in certain contexts. ### Step 3: Analyze the third statement **Statement:** CO can reduce the aqueous solution of PdCl2 to metallic Pd. - **Explanation:** This statement is true as well. Carbon monoxide (CO) is a strong reducing agent and can reduce palladium(II) chloride (PdCl2) in an aqueous solution to metallic palladium (Pd), producing carbon dioxide (CO2) and hydrochloric acid (HCl) as byproducts. ### Step 4: Analyze the fourth statement **Statement:** Cu forms a complex with hemoglobin and this complex is less stable than oxyhemoglobin. - **Explanation:** This statement is incorrect. Hemoglobin contains iron (Fe) as its metal center, not copper (Cu). While CO can bind to hemoglobin, forming carboxyhemoglobin, this statement incorrectly attributes the formation of a complex to copper. The stability of the CO-hemoglobin complex is actually greater than that of oxyhemoglobin, making this statement false. ### Conclusion The incorrect statement about CO is the fourth one: "Cu forms a complex with hemoglobin and this complex is less stable than oxyhemoglobin." ---
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