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The reaction of ethyl p - amiobenzoate w...

The reaction of ethyl p - amiobenzoate with `HNO_2` and then with `HBF_4` yields a compounds (X), a crystalline ionic compound. Compound (X) , when heated forms `C_9H_9O_2F`(Y). The compound (Y) is

A

ethyl p - fluorobenzoate

B

ethyl o - fluorobenzoate

C

ethyl m - fluorobenzoate

D

mixture of all the above

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The correct Answer is:
To solve the problem, we need to understand the reactions involved and the compounds formed step by step. ### Step 1: Identify the starting compound The starting compound is ethyl para-aminobenzoate. Its structure can be represented as follows: - **Structure**: - Ethyl group (C2H5) attached to the carboxylate (COO-) group of benzoic acid. - An amino group (NH2) is located at the para position relative to the carboxylate group. ### Step 2: Reaction with HNO2 When ethyl para-aminobenzoate reacts with nitrous acid (HNO2), it forms a diazonium salt. The amino group (-NH2) is converted into a diazonium group (-N2+). - **Reaction**: - Ethyl para-aminobenzoate + HNO2 → Ethyl para-diazobenzenoate (Compound X) ### Step 3: Reaction with HBF4 The diazonium salt formed in the previous step is then treated with tetrafluoroboric acid (HBF4). This reaction leads to the formation of a crystalline ionic compound, which is the tetrafluoroborate salt of the diazonium compound. - **Reaction**: - Ethyl para-diazobenzenoate + HBF4 → Ethyl para-diazobenzenoate tetrafluoroborate (Compound X) ### Step 4: Heating Compound X When Compound X is heated, it undergoes a decomposition reaction. During this process, nitrogen gas (N2) is released, and the diazonium group is replaced by a fluorine atom from the BF4- ion, resulting in the formation of ethyl para-fluorobenzoate. - **Decomposition Reaction**: - Ethyl para-diazobenzenoate tetrafluoroborate (X) → Ethyl para-fluorobenzoate (Y) + N2 + BF3 ### Step 5: Identify Compound Y The final compound formed after heating is ethyl para-fluorobenzoate. Its molecular formula is C9H9O2F, which matches the given formula for compound Y. - **Compound Y**: Ethyl para-fluorobenzoate (C9H9O2F) ### Final Answer The compound (Y) is **ethyl para-fluorobenzoate**. ---
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