The following reaction `R-CH_2CH_2overset(+)N(CH_3)_3OH^(-)` is called `overset(Delta)rarrRCH=CH_2+N(CH_3)_3+H_2O`

Options

A. Hoffmann - bromamide reaction
B. Cope elimination
C. Hoffmann elimination
D. Beckmann rearrangement

Answer

To solve the given reaction, we need to analyze the components and the process involved step-by-step. The reaction is:

\[ R-CH_2CH_2 + N(CH_3)_3OH^- \rightarrow RCH=CH_2 + N(CH_3)_3 + H_2O \]

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactants in this reaction are an alkyl chain (R-CH2CH2) and a quaternary ammonium hydroxide (N(CH3)3OH^-). The alkyl chain has two carbon atoms and a functional group (R).

**Hint:** Look for the structure of the reactants and their functional groups.

2. **Formation of Tetraamine Salt:**
- The quaternary ammonium hydroxide (N(CH3)3OH^-) acts as a base. It can deprotonate the alkyl chain, resulting in the formation of a tetraamine salt.

**Hint:** Recognize that the ammonium compound can stabilize the positive charge through resonance.

3. **Elimination Reaction:**
- The hydroxide ion (OH^-) will abstract a proton (H+) from the alkyl chain, leading to the formation of a double bond between the two carbon atoms (C=C). This process is known as elimination.

**Hint:** Remember that elimination reactions typically involve the removal of a small molecule (like water) and the formation of a double bond.

4. **Formation of Products:**
- The products of the reaction are:
- An alkene (RCH=CH2)
- A quaternary ammonium compound (N(CH3)3)
- Water (H2O)

**Hint:** Ensure to balance the reaction by accounting for all atoms in the reactants and products.

5. **Naming the Reaction:**
- This reaction is classified as a **Hofmann Elimination Reaction**. It is characterized by the conversion of a quaternary ammonium salt into an alkene, with the loss of a small molecule (water in this case).

**Hint:** Familiarize yourself with different types of elimination reactions and their specific names.

### Final Reaction Equation:
The overall reaction can be summarized as:
\[ R-CH_2CH_2 + N(CH_3)_3OH^- \rightarrow RCH=CH_2 + N(CH_3)_3 + H_2O \]

### Summary:
The reaction involves the transformation of a quaternary ammonium hydroxide and an alkyl chain into an alkene, a quaternary ammonium compound, and water, and is known as the Hofmann elimination reaction.