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The percentage of Se in peroxides enzyme...

The percentage of Se in peroxides enzyme is 0.5% by mass (atomic mass of Se = 78.4 amu). Then , the minimum molecular mass of enzyme which contains not more than one Se atom is

A

`1.568 xx10^4` amu

B

`1.568 xx10^7` amu

C

`1.568 xx10^3` amu

D

`1.568 xx10^6` amu

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The correct Answer is:
To find the minimum molecular mass of the enzyme that contains not more than one selenium (Se) atom, we can follow these steps: ### Step 1: Understand the given information - Percentage of Se in the enzyme = 0.5% by mass - Atomic mass of Se = 78.4 amu ### Step 2: Set up the equation The percentage by mass of an element in a compound is given by the formula: \[ \text{Percentage of element} = \left( \frac{\text{mass of element}}{\text{molar mass of compound}} \right) \times 100 \] In this case, we can rearrange the formula to find the molar mass of the enzyme (W): \[ 0.5 = \left( \frac{78.4}{W} \right) \times 100 \] ### Step 3: Rearranging the equation Rearranging the equation to solve for W gives: \[ W = \frac{78.4 \times 100}{0.5} \] ### Step 4: Calculate W Now, we can calculate W: \[ W = \frac{7840}{0.5} = 15680 \text{ amu} \] ### Step 5: Conclusion The minimum molecular mass of the enzyme, which contains not more than one Se atom, is **15680 amu**. ---
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