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Consider the following compounds 1. Ph...

Consider the following compounds
1. Phenol
2. o - chlorophenol
3. m - chloropheonl
4. p - chlorophenol
Place these compounds in the decreasing order of acidity

A

`1 gt 2 gt 3 gt 4`

B

`2 gt 3 gt 4 gt 1 `

C

`3 gt 4 gt 1 gt 2 `

D

`2 gt 3 gt 1 gt 4 `

Text Solution

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The correct Answer is:
To determine the decreasing order of acidity for the compounds given (Phenol, o-chlorophenol, m-chlorophenol, and p-chlorophenol), we need to analyze the effects of the chlorine substituent on the acidity of phenol. ### Step 1: Understand Acidity Acidity is the ability of a compound to donate a proton (H+). The stability of the resulting negative charge (conjugate base) after deprotonation is crucial in determining the strength of the acid. The more stable the conjugate base, the stronger the acid. ### Step 2: Analyze Phenol - **Phenol (C6H5OH)**: When phenol donates a proton, it forms the phenoxide ion (C6H5O−). The negative charge on the oxygen is stabilized by resonance with the aromatic ring, making phenol a weak acid. ### Step 3: Analyze o-Chlorophenol - **o-Chlorophenol**: The chlorine atom is an electron-withdrawing group (due to its electronegativity) and can stabilize the negative charge on the phenoxide ion through resonance (ortho effect). This stabilization increases the acidity compared to phenol. ### Step 4: Analyze m-Chlorophenol - **m-Chlorophenol**: The chlorine atom is in the meta position. In this case, it does not participate in resonance with the negative charge on the oxygen. The only effect it has is a -I (inductive effect), which slightly decreases the acidity compared to phenol, but not as much as o-chlorophenol. ### Step 5: Analyze p-Chlorophenol - **p-Chlorophenol**: The chlorine atom is in the para position. Similar to o-chlorophenol, it can stabilize the negative charge on the phenoxide ion through resonance. This makes p-chlorophenol more acidic than both phenol and m-chlorophenol. ### Step 6: Order the Acidity Based on the analysis: 1. **o-Chlorophenol** (most acidic due to strong resonance stabilization) 2. **p-Chlorophenol** (also has resonance stabilization but less effective than ortho) 3. **Phenol** (moderate acidity due to resonance stabilization) 4. **m-Chlorophenol** (least acidic due to lack of resonance stabilization) ### Final Order of Acidity The decreasing order of acidity is: **o-Chlorophenol > p-Chlorophenol > Phenol > m-Chlorophenol**
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