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The degree of dissociation (alpha) of a...

The degree of dissociation `(alpha)` of a weak electrolyte `A_(x)B_(y)` is related to van't Hoff factor (i) by the expression

A

`alpha=(i-1)/(x+y+1)`

B

`alpha=(i-1)/(x+y-1)`

C

`alpha=(x+y-1)/(i-1)`

D

`alpha=(x+y+1)/(i-1)`

Text Solution

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The correct Answer is:
B
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