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For the reaction between CO2 and graphit...

For the reaction between `CO_2` and graphite `CO_2(g)+C(s) hArr2CO(g)`
`DeltaH=+170.0kJ and DeltaS = 170 JK^(-1)`. The reaction is spontaneous at

A

298 K

B

500 K

C

900 K

D

1200 K

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The correct Answer is:
To determine when the reaction between \( CO_2 \) and graphite becomes spontaneous, we can use the Gibbs free energy equation: \[ \Delta G = \Delta H - T \Delta S \] ### Step 1: Identify the given values We are given: - \( \Delta H = +170.0 \, \text{kJ} \) - \( \Delta S = 170 \, \text{J/K} \) ### Step 2: Convert \( \Delta H \) to Joules Since \( \Delta S \) is in Joules, we need to convert \( \Delta H \) from kJ to J: \[ \Delta H = 170.0 \, \text{kJ} \times 1000 \, \text{J/kJ} = 170000 \, \text{J} \] ### Step 3: Set up the equation for spontaneity For the reaction to be spontaneous, \( \Delta G \) must be less than 0: \[ \Delta G < 0 \implies \Delta H - T \Delta S < 0 \] ### Step 4: Rearrange the equation Rearranging gives us: \[ \Delta H < T \Delta S \] or \[ T > \frac{\Delta H}{\Delta S} \] ### Step 5: Substitute the values Substituting the values we have: \[ T > \frac{170000 \, \text{J}}{170 \, \text{J/K}} = 1000 \, \text{K} \] ### Step 6: Conclusion The reaction is spontaneous at temperatures greater than \( 1000 \, \text{K} \). ### Final Answer The reaction is spontaneous at temperatures greater than \( 1000 \, \text{K} \). ---
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