Consider the following sequence of reaction and identify the final product (Z). `CH_3COOHoverset(Ca(OH)_2)rarr(X)overset(Delta)rarr(Y)overset(NH_2OH)rarr(Z)`

Options

A. Ethanol oxime
B. Methanal oxime
C. Propanone oxime
D. 2 - nitrosopropane

Answer

To determine the final product (Z) from the given sequence of reactions, we will break down each step of the reaction process.

### Step 1: Reaction of Acetic Acid with Calcium Hydroxide
The first reaction involves acetic acid (CH₃COOH) reacting with calcium hydroxide (Ca(OH)₂). This is an acid-base reaction, leading to the formation of calcium acetate.

**Reaction:**
\[ \text{CH}_3\text{COOH} + \text{Ca(OH)}_2 \rightarrow \text{CH}_3\text{COO}^-\text{Ca}^{2+} + 2\text{H}_2\text{O} \]

**Product (X):** Calcium acetate, which can be represented as:
\[ \text{X} = \text{CH}_3\text{COO}\text{Ca} \]

### Step 2: Heating Calcium Acetate
Next, we heat the calcium acetate (X). During this dry distillation, calcium acetate decomposes to form acetone (propanone), calcium oxide (CaO), and carbon dioxide (CO₂).

**Reaction:**
\[ \text{CH}_3\text{COO}\text{Ca} \xrightarrow{\Delta} \text{CH}_3\text{C(=O)CH}_3 + \text{CaO} + \text{CO}_2 \]

**Product (Y):** Acetone (propanone), which can be represented as:
\[ \text{Y} = \text{CH}_3\text{C(=O)CH}_3 \]

### Step 3: Reaction of Acetone with Hydroxylamine
The final step involves the reaction of acetone (Y) with hydroxylamine (NH₂OH). This reaction forms an oxime, specifically propanone oxime.

**Reaction:**
\[ \text{CH}_3\text{C(=O)CH}_3 + \text{NH}_2\text{OH} \rightarrow \text{CH}_3\text{C(=N-OH)CH}_3 + \text{H}_2\text{O} \]

**Final Product (Z):** Propanone oxime, which can be represented as:
\[ \text{Z} = \text{CH}_3\text{C(=N-OH)CH}_3 \]

### Conclusion
The final product (Z) is propanone oxime.

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