Identify the final product (Z) in the following sequence of reaction.
`C_6H_(13)COCloverset("H_2,Pd//BaSO_4)rarr(X)overset(C_6H_(13)NH_2)rarr (Y)overset(H_2//Ni)rarr(Z)`

Options

A. `C_6H_(13)CH_2NHC_6H_(13)`
B. `C_(12)H_(25)CH_2NH_2`
C. `C_6H_(13)-underset(C_6H_14)underset(|)(CH)-NH_2`
D. `(C_6H_(13))_2CH_3N`

Answer

To identify the final product (Z) in the given sequence of reactions, we will follow the steps outlined in the reaction sequence.

### Step-by-Step Solution:

1. **Identify the starting compound (C6H13COCl)**:
- The compound is an acyl chloride (specifically, hexanoyl chloride) with the formula C6H13COCl.

2. **First Reaction: Rosenmund Reduction**:
- The acyl chloride (C6H13COCl) is treated with hydrogen gas (H2) in the presence of palladium on barium sulfate (Pd/BaSO4).
- This reaction is known as the Rosenmund reduction, which converts acyl chlorides into aldehydes.
- The product (X) of this reaction will be C6H13CHO (hexanal).

3. **Second Reaction: Reaction with Amine (C6H13NH2)**:
- The aldehyde (C6H13CHO) is then reacted with a primary amine (C6H13NH2).
- The reaction between an aldehyde and a primary amine leads to the formation of an imine (C6H13CH=NH).
- The product (Y) of this reaction will be C6H13CH=NH.

4. **Third Reaction: Hydrogenation**:
- The imine (C6H13CH=NH) is subjected to hydrogenation in the presence of nickel (Ni) as a catalyst.
- Hydrogenation of an imine will convert it into an amine by adding hydrogen across the double bond.
- The final product (Z) will be C6H13CH2NH2 (hexylamine).

### Final Product:
- The final product (Z) is C6H13CH2NH2, which is hexylamine.

### Summary of Products:
- X = C6H13CHO (hexanal)
- Y = C6H13CH=NH (imine)
- Z = C6H13CH2NH2 (hexylamine)