In the reaction sequence `CH_3-CH_2-CH_2-Broverset(AgCN) rarr (X) overset (H_2O/ H^(+))rarr(Y)` (Y) will be

Options

A. `CH_3-CH_2-CH_2-NH_2`
B. `CH_3-CH_2-NH_2`
C. `CH_3(CH_2)_2-CH_2-NH_2`
D. `CH_3-(CH_2)_3-CH_2-NH_2`

Answer

To solve the given reaction sequence, we will break down the steps involved in the transformation of the starting compound to the final product.

### Step-by-Step Solution:

1. **Identify the Starting Compound**:
The starting compound is `CH3-CH2-CH2-Br` (1-bromopropane).

2. **First Reaction with AgCN**:
- In the first step, the compound reacts with `AgCN`.
- Here, `AgCN` acts as a source of the nucleophile `CN^-` (cyanide ion).
- The bromine atom (Br) is a good leaving group, and the cyanide ion will attack the carbon atom bonded to the bromine.
- The reaction can be represented as:
\[ CH3-CH2-CH2-Br + AgCN \rightarrow CH3-CH2-CH2-CN + AgBr \]
- The product `X` is `CH3-CH2-CH2-CN` (propionitrile).

3. **Hydrolysis of the Nitrile (X) to form Y**:
- The next step involves hydrolysis of the nitrile in the presence of water and an acid (H+).
- The nitrile group (`-CN`) undergoes hydrolysis to form a carboxylic acid.
- The reaction can be represented as:
\[ CH3-CH2-CH2-CN + H2O \xrightarrow{H^+} CH3-CH2-CH2-COOH \]
- The product `Y` is `CH3-CH2-CH2-COOH` (propanoic acid).

### Final Answer:
The final compound (Y) will be **propanoic acid** (CH3-CH2-CH2-COOH).

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