Identify product (Z) in the following sequence of chemical reactions:
`CH_3CNoverset(C_2H_5OH//Na)rarr(X)overset(HNO_2)underset(H_2O)rarr(Y)overset([0])underset("Strongoxidisingagent")rarr(Z)`

Options

A. `CH_3COOH`
B. `CH_3CONH_2`
C. `CH_3CN`
D. `CH_3COOOH`

Answer

To solve the problem step by step, we will analyze the given sequence of reactions and identify the product (Z) at the end.

### Step 1: Identify the starting compound
The starting compound is **CH₃CN** (acetonitrile).

### Step 2: Reaction with ethanol and sodium
When CH₃CN is treated with **C₂H₅OH** (ethanol) in the presence of **Na** (sodium), the sodium acts as a reducing agent. This reaction converts the nitrile (CH₃CN) into a primary amine (X).

**Product (X)**: CH₃CH₂NH₂ (ethylamine)

### Step 3: Reaction with HNO₂ and H₂O
Next, the primary amine (X) is treated with **HNO₂** (sodium nitrite) and **H₂O**. This reaction leads to the formation of a diazonium salt, which can undergo tautomerization.

The reaction can be represented as:
1. The primary amine reacts with nitrous acid to form a diazonium salt.
2. The diazonium salt can undergo tautomerization to form an alcohol.

**Product (Y)**: CH₃OH (methanol)

### Step 4: Reaction with a strong oxidizing agent
The final step involves treating the alcohol (Y) with a **strong oxidizing agent**. Strong oxidizing agents can oxidize alcohols to carboxylic acids.

In this case, methanol (Y) will be oxidized to form **ethanoic acid** (acetic acid).

**Product (Z)**: CH₃COOH (ethanoic acid)

### Final Answer
Therefore, the final product (Z) is **CH₃COOH** (ethanoic acid).

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