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Which of the following is most easily hy...

Which of the following is most easily hydrolysed with aqueous KOH solution ?

A

`CH_3Cl`

B

`C_6H_5CH_2Cl`

C

`CH_2=CHCl`

D

`C_6H_5-underset(Cl)underset(|)(CH)-CH_3`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds is most easily hydrolyzed with aqueous KOH solution, we need to analyze the stability of the carbocations formed during the hydrolysis process. ### Step-by-Step Solution: 1. **Understanding Hydrolysis with KOH**: Hydrolysis of alkyl halides involves the substitution of the halide ion (like Cl, Br, etc.) with hydroxide ion (OH⁻) from KOH. This process often leads to the formation of a carbocation intermediate. 2. **Formation of Carbocations**: When an alkyl halide undergoes hydrolysis, the halide ion leaves, forming a carbocation. The stability of this carbocation is crucial because more stable carbocations will lead to faster hydrolysis. 3. **Evaluating Carbocation Stability**: The stability of carbocations can be ranked as follows: - Tertiary carbocations (3°) > Secondary carbocations (2°) > Primary carbocations (1°) > Methyl carbocations (CH₃⁺). - Additionally, resonance stabilization can significantly enhance carbocation stability. 4. **Analyzing Given Compounds**: Let's assume we have four different alkyl halides to consider: - Compound A: CH₃Cl (Methyl chloride) - Compound B: CH₂=CHCl (Vinyl chloride) - Compound C: C₆H₅CH₂Cl (Benzyl chloride) - Compound D: C₆H₅CHCl (Allyl chloride) Now, we analyze the carbocations formed from each compound: - **Compound A**: Forms a methyl carbocation (CH₃⁺) which is very unstable. - **Compound B**: Forms a vinyl carbocation (CH₂=CH⁺) which is also unstable due to lack of stability from resonance. - **Compound C**: Forms a benzyl carbocation (C₆H₅CH₂⁺) which is stabilized by resonance from the benzene ring. - **Compound D**: Forms an allyl carbocation (C₆H₅CH⁺) which is also stabilized by resonance but less than benzyl. 5. **Conclusion**: Among the compounds analyzed, **Compound C (Benzyl chloride)** forms the most stable carbocation due to resonance stabilization from the adjacent benzene ring. Therefore, it will be hydrolyzed most easily in aqueous KOH solution. ### Final Answer: **Benzyl chloride (C₆H₅CH₂Cl) is most easily hydrolyzed with aqueous KOH solution.**
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