In the given reaction `C_6H_5-underset(O)underset(||)C-CH_3overset(NH_2OH//H^(o+))rarr[X]overset(Na//C_2H_5OH)rarr[Y]`
[Y] will be

Options

A. `C_6H_5-underset(CH_3)underset(|)(CH)-NH_2`
B. `C_6H_5-underset(CH_3)underset(|)(CH)-NH-CH_3`
C. `C_6H_5-overset(O)overset(||)C-NH-CH_3`
D. `CH_3-overset(O)overset(||)C-NH-C_6H_5`

Answer

To solve the given reaction step by step, let's analyze the reaction and identify the products formed.

### Step 1: Identify the starting compound
The starting compound is `C6H5-C(=O)-CH3`, which is acetophenone (a ketone).

### Step 2: Reaction with hydroxylamine
When acetophenone reacts with hydroxylamine (`NH2OH`) under acidic conditions, it forms an oxime. The reaction can be represented as follows:

\[ C6H5-C(=O)-CH3 + NH2OH \rightarrow C6H5-C(=NOH)-CH3 \]

This product is known as acetoxime.

### Step 3: Identify the product [X]
The product formed after the reaction with hydroxylamine is `C6H5-C(=NOH)-CH3`, which we denote as [X].

### Step 4: Reduction with sodium in ethanol
The next step involves the reduction of the oxime [X] using sodium (`Na`) in ethanol (`C2H5OH`). Sodium acts as a reducing agent and converts the oxime into an amine. The reaction can be represented as follows:

\[ C6H5-C(=NOH)-CH3 + Na \rightarrow C6H5-CH(NH2)-CH3 \]

### Step 5: Identify the final product [Y]
The final product formed after the reduction is `C6H5-CH(NH2)-CH3`, which is an amine. This compound can be named as 1-phenylpropan-2-amine.

### Conclusion
Thus, the final product [Y] is 1-phenylpropan-2-amine.

### Summary of the Steps
1. Start with acetophenone (C6H5-C(=O)-CH3).
2. React with hydroxylamine to form acetoxime (C6H5-C(=NOH)-CH3).
3. Reduce the oxime with sodium in ethanol to form an amine (C6H5-CH(NH2)-CH3).