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When 0.01 moles of NaOH are added to 1 l...

When 0.01 moles of NaOH are added to 1 litre of a buffer solution , its pH changes from 4.745 to 4.832. The buffer capacity is

A

0.0115

B

11.5

C

0.115

D

None

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The correct Answer is:
To find the buffer capacity of the solution, we can follow these steps: ### Step 1: Understand the concept of buffer capacity Buffer capacity is defined as the amount of acid or base that can be added to a buffer solution before a significant change in pH occurs. It can be calculated using the formula: \[ \text{Buffer Capacity} = \frac{\text{Number of moles of strong base or acid added}}{\text{Change in pH}} \] ### Step 2: Identify the given values From the problem, we have: - Number of moles of NaOH added = 0.01 moles - Initial pH = 4.745 - Final pH = 4.832 ### Step 3: Calculate the change in pH To find the change in pH, we subtract the initial pH from the final pH: \[ \text{Change in pH} = \text{Final pH} - \text{Initial pH} = 4.832 - 4.745 \] Calculating this gives: \[ \text{Change in pH} = 0.087 \] ### Step 4: Calculate the buffer capacity Now we can substitute the values into the buffer capacity formula: \[ \text{Buffer Capacity} = \frac{0.01 \text{ moles}}{0.087} \] Calculating this gives: \[ \text{Buffer Capacity} \approx 0.1149 \] ### Step 5: Round the answer We can round this to three decimal places: \[ \text{Buffer Capacity} \approx 0.115 \] ### Final Answer Thus, the buffer capacity of the solution is approximately **0.115**. ---
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