Silver cyanide `overset(Delta)rarr"Silver"+Aoverset(OH^-)rarrX+Y+H_2O` In the above sequence of reaction A,X,Y are respectively.

Options

A. `Cbar(N),(CN)_2,HCN`
B. `(CN)_2,CbarN,OCbarN`
C. `(CN)_2,N_2OCN`
D. `(CN)_2,C_2^(2-),NO_2^-`

Answer

To solve the given question step by step, we will analyze the reactions involving silver cyanide (AgCN) and the products formed during the reactions.

### Step 1: Identify the initial reaction
The first part of the reaction involves heating silver cyanide (AgCN):
\[ \text{AgCN} \xrightarrow{\Delta} \text{Ag} + \text{A} \]

When silver cyanide is heated, it decomposes to form silver (Ag) and another product, which we will identify as A.

### Step 2: Determine product A
During the decomposition of AgCN:
- The cyanide ion (CN) does not remain as a single entity. Instead, it can dimerize to form cyanogen (C2N2).
Thus, we can conclude:
\[ \text{A} = \text{C}_2\text{N}_2 \]

### Step 3: Reaction with hydroxide ions (OH^-)
The next part of the reaction involves the product A (C2N2) reacting with hydroxide ions (OH^-):
\[ \text{C}_2\text{N}_2 + \text{OH}^- \rightarrow \text{X} + \text{Y} + \text{H}_2\text{O} \]

### Step 4: Identify products X and Y
When cyanogen (C2N2) reacts with hydroxide ions, it can be hydrolyzed to form:
- Cyanide ion (CN^-)
- Thiocyanate ion (OCN^-)

Thus, we can conclude:
- \( \text{X} = \text{CN}^- \)
- \( \text{Y} = \text{OCN}^- \)

### Final Answer
So, the final products A, X, and Y are:
- A = C2N2
- X = CN^-
- Y = OCN^-

### Summary of the answer:
- A = C2N2
- X = CN^-
- Y = OCN^-