In the given reaction `CH_3-CH_2-C-=Noverset((i)CH_3MgCl)rarr[X]` [X] will be

Options

A. `CH_3-CH_2-overset(O)overset(||)C-CH_2-CH_3`
B. `CH_3-CH_2-overset(O)overset(||)C-CH_3`
C. `C_2H_5-underset(CH_3)underset(|)overset(OH)overset(|)C-C_2H_5OH`
D. `C_2H_5-underset(CH_3)underset(|)overset(OH)overset(|)C-CH_5`

Answer

To solve the given reaction `CH_3-CH_2-C≡N + CH_3MgCl → [X]`, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- An alkyne: `CH3-CH2-C≡N` (which is propyne)
- Grignard reagent: `CH3MgCl`

### Step 2: Understand the Grignard Reagent
Grignard reagents are strong nucleophiles. The `CH3MgCl` will dissociate into `CH3^-` (methyl anion) and `MgCl^+`. The methyl anion will act as a nucleophile.

### Step 3: Nucleophilic Attack
The nucleophilic methyl anion (`CH3^-`) will attack the carbon atom that is triple-bonded to nitrogen in `CH3-CH2-C≡N`. This will break the triple bond and form a new carbon-carbon bond.

### Step 4: Formation of Intermediate
After the nucleophilic attack, we will have an intermediate that looks like this:
```
CH3-CH2-C(=N)CH3
```
This intermediate has a nitrogen atom that is now bonded to two carbon atoms.

### Step 5: Protonation
The nitrogen in the intermediate has a lone pair of electrons and can abstract a proton from a solvent (like water or any other proton donor). This will lead to the formation of an amine.

### Step 6: Final Product
After protonation, the final product will be:
```
CH3-CH2-C(=NH)-CH3
```
This is an imine, which can further rearrange or react depending on the conditions, but in this case, it is stable enough to be considered the final product.

### Conclusion
Thus, the final product `[X]` is `CH3-CH2-C(=NH)-CH3`.