In the given reaction `CH_3-underset(C_3H_7)underset(|)overset(C_2H_5)overset(|)C-Broverset(NaI//HOH//"Acetone")rarr[X]`
[X] will be

Options

A. `CH_3-underset(C_3H_7)underset(|)overset(C_2H_5)overset(|)C-I`
B. `I-underset(C_3H_7)underset(|)overset(C_2H_5)overset(|)C-CH_3`
C. Mixture of A and B
D. None of these

Answer

To solve the given reaction, we need to analyze the reactant and the reagents involved. The reaction involves a tertiary alkyl halide that undergoes a nucleophilic substitution reaction with NaI in the presence of water and acetone.

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant is a tertiary alkyl halide, which is characterized by having a halogen (Br in this case) attached to a carbon that is connected to three other carbon atoms.

2. **Understanding the Role of NaI**: Sodium iodide (NaI) dissociates into Na⁺ and I⁻ ions in solution. Here, I⁻ acts as a nucleophile.

3. **Determine the Mechanism**: Since the reactant is a tertiary alkyl halide, the reaction will likely proceed via the SN1 mechanism. In SN1 reactions, the first step involves the formation of a carbocation after the leaving group (Br) departs.

4. **Formation of Carbocation**: The Br group will leave, resulting in the formation of a tertiary carbocation. This carbocation is stabilized due to the presence of three alkyl groups.

5. **Nucleophilic Attack**: The I⁻ nucleophile can then attack the carbocation. Since the carbocation is planar, the nucleophile can attack from either side of the planar structure, leading to the formation of two possible products.

6. **Products Formation**: The two products formed will be:
- One where the I⁻ attacks from one side (let's call this Product A).
- Another where the I⁻ attacks from the opposite side (let's call this Product B).

7. **Final Product**: Since both products A and B can be formed due to the nature of the carbocation and the nucleophilic attack, the final answer will be a mixture of both products.

### Conclusion:
The product [X] will be a mixture of both products A and B.