Match list I with list II and select this correct answer using the codes given below the lists.
`{:(,"List - I",,"List - II"),((p),"Nucleic acids",1.,DNA),((q),"Uracil",2.,"Hormones"),((r),"Thymine",3.,"Polynucleotides"),((s),"Double - helix structure",4.,"RNA"):}`

Options

A. `(p)-4,(q)-3,(r)-1,(s)-1`
B. `(p)-3,(q)-4,(r)-1,(s)-1`
C. `(p)-3,(q)-1,(r)-4,(s)-1`
D. `(p)-3,(q)-1,(r)-1,(s)-4`

Answer

To solve the problem of matching List I with List II, let's analyze each item in both lists step by step.

### Step 1: Analyze List I
- **P: Nucleic acids**
- **Q: Uracil**
- **R: Thymine**
- **S: Double-helix structure**

### Step 2: Analyze List II
- **1: DNA**
- **2: Hormones**
- **3: Polynucleotides**
- **4: RNA**

### Step 3: Match each item from List I with List II

1. **Matching S (Double-helix structure)**:
- The double-helix structure is characteristic of DNA. Therefore, S matches with **1 (DNA)**.

2. **Matching P (Nucleic acids)**:
- Nucleic acids include both DNA and RNA, which are types of polynucleotides. Therefore, P matches with **3 (Polynucleotides)**.

3. **Matching R (Thymine)**:
- Thymine is a nitrogenous base found in DNA but not in RNA. Therefore, R matches with **1 (DNA)** as well, but we already matched DNA with S. So, we will consider that R is related to DNA.

4. **Matching Q (Uracil)**:
- Uracil is a nitrogenous base found in RNA. Therefore, Q matches with **4 (RNA)**.

### Summary of Matches
- P (Nucleic acids) → 3 (Polynucleotides)
- Q (Uracil) → 4 (RNA)
- R (Thymine) → 1 (DNA)
- S (Double-helix structure) → 1 (DNA)

### Final Matching
- P → 3
- Q → 4
- R → 1
- S → 1

### Conclusion
Based on the analysis, the correct matches are:
- P → 3
- Q → 4
- R → 1
- S → 1