`CH_3-C-=Noverset(H_2"O"//Delta)rarr(A)overset(H_2"O"//H^+)rarr(B)(A) and (B)` respectively are

Options

A. `CH_3-overset(O)overset(||)C-NH_2and CH_3COOH`
B. `CH_3COONH_4and CH_3COOH`
C. `CH_3CONH_2 and CH_3COONH_4`
D. `CH_3-CH=NH and CH_3COOH`

Answer

To solve the question, we need to analyze the reactions of CH₃CN (acetonitrile) with water (H₂O) under different conditions.

### Step-by-Step Solution:

1. **Identify the Reactant:**
The starting compound is CH₃CN, which is acetonitrile.

2. **Partial Hydrolysis of CH₃CN:**
When CH₃CN reacts with water (H₂O) under mild conditions (without strong acid or base), it undergoes partial hydrolysis. This means it is converted into an amide.
- The reaction can be represented as:
\[ \text{CH}_3\text{CN} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{C(O)NH}_2 \quad \text{(Amide)} \]
- The product formed (A) is **acetamide (CH₃C(O)NH₂)**.

3. **Complete Hydrolysis of Acetamide:**
Next, when acetamide (A) undergoes hydrolysis in the presence of an acid (H⁺), it is completely hydrolyzed to form a carboxylic acid and ammonia.
- The reaction can be represented as:
\[ \text{CH}_3\text{C(O)NH}_2 + \text{H}_2\text{O} \xrightarrow{\text{H}^+} \text{CH}_3\text{COOH} + \text{NH}_3 \]
- The product formed (B) is **acetic acid (CH₃COOH)**.

4. **Final Products:**
- Therefore, the structures of A and B are:
- A: Acetamide (CH₃C(O)NH₂)
- B: Acetic Acid (CH₃COOH)

### Conclusion:
The final answer is:
- (A) Acetamide (CH₃C(O)NH₂)
- (B) Acetic Acid (CH₃COOH)