Compound A on oxidation with not `KMnO_4//bar(O)H` given two compound `CH_3-underset(CH_3)underset(|)(CH)-COOH and CH_3-overset(O)overset(||)C-CH_2-CH_2-CH_3`. Compound A will have the structure

Options

A. `CH_3-CH_2-underset(CH_3)underset(|)C=underset(CH_3)underset(|)C-CH_2-CH_3`
B. `CH_3-underset(CH_3)underset(|)(CH)-CH=underset(CH_3)underset(|)C-CH_2-CH_2-CH_3`
C. `CH_3-underset(CH_3)underset(|)(CH)-C-=C-CH_3`
D. `CH_3-underset(CH_3)underset(|)(CH)-C-=C-underset(CH_3)underset(|)(CH)-CH_3`

Answer

To determine the structure of Compound A that, upon oxidation with hot KMnO4 in the presence of OH-, yields the two compounds \( CH_3-CH(CH_3)-COOH \) and \( CH_3-C(=O)-CH_2-CH_2-CH_3 \), we will follow these steps:

### Step 1: Analyze the Products
The products of the oxidation are:
1. \( CH_3-CH(CH_3)-COOH \) - This is a carboxylic acid, indicating that one of the carbons in Compound A was a primary carbon that got oxidized to form the carboxylic acid.
2. \( CH_3-C(=O)-CH_2-CH_2-CH_3 \) - This is a ketone, indicating that one of the carbons in Compound A was a secondary carbon that got oxidized to form the ketone.

### Step 2: Identify the Functional Groups
From the products, we can deduce that Compound A must contain:
- A double bond (alkene) since KMnO4 oxidizes alkenes.
- The presence of both a primary and a secondary carbon in the structure.

### Step 3: Construct the Possible Structure
To construct the structure of Compound A, we need to consider a double bond that can lead to the formation of both a carboxylic acid and a ketone upon oxidative cleavage.

1. The carboxylic acid \( CH_3-CH(CH_3)-COOH \) suggests that the double bond must be adjacent to a carbon that can be oxidized to a carboxylic acid.
2. The ketone \( CH_3-C(=O)-CH_2-CH_2-CH_3 \) suggests that the other part of the double bond must lead to a secondary carbon.

### Step 4: Propose a Structure for Compound A
Based on the above analysis, we can propose that Compound A has the following structure:
- The double bond is between the carbon that will become the ketone and the carbon that will become the carboxylic acid.

Thus, the structure of Compound A can be represented as:
\[ CH_3-CH=CH-CH_2-CH_3 \]

### Step 5: Verify the Structure
To verify:
- Upon oxidation with KMnO4, the double bond between \( CH_3-CH \) and \( CH \) will cleave.
- The \( CH_3-CH \) (primary) will be oxidized to \( COOH \).
- The \( CH \) (secondary) will be oxidized to form the ketone.

### Final Answer
The structure of Compound A is:
\[ CH_3-CH=CH-CH_2-CH_3 \]

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