In the given reaction `C_6H_5-overset(O)overset(||)C-overset(O)overset(||)C-C_6H_5overset((i)CH_3MgBr("excess"))underset((ii)HOH//H^(o+))rarr` "Product
Product will be

Options

A. `C_6H_5-underset(CH_3)underset(|)overset(OH)overset(|)C-overset(OH)overset(|)underset(CH_3)underset(|)C-C_6H_5`
B. `C_6H_5-overset(OH)overset(|)underset(CH_3)underset(|)C-overset(O)overset(||)C-C_6H_5`
C. `C_6H_5-COOH`
D. `C_6H_5-CHOH-CHOH-C_6H_5`

Answer

To solve the given reaction step by step, we will analyze the reaction involving the Grignard reagent and the carbonyl compound. The reaction is as follows:

1. **Identify the Reactants**: The reactants are two phenyl groups (C6H5) connected by a carbon chain with two carbonyl (C=O) groups in between. The structure can be represented as:
\[ C_6H_5 - C(=O) - C(=O) - C_6H_5 \]

2. **Recognize the Grignard Reagent**: The Grignard reagent used is methyl magnesium bromide (CH3MgBr). This reagent acts as a nucleophile, meaning it can donate a pair of electrons to an electrophile.

3. **Nucleophilic Attack**: The carbonyl carbon (C=O) is electrophilic and will be attacked by the nucleophilic carbon from the Grignard reagent. Since there are two carbonyl groups, the Grignard reagent can attack either of them. We will consider the attack on the first carbonyl group:
\[ C_6H_5 - C(=O) - C(=O) - C_6H_5 + CH_3MgBr \rightarrow C_6H_5 - C(OH)(C_6H_5) - C(=O) - C_6H_5 \]
After the attack, we will have a negatively charged oxygen (alkoxide) and a new carbon-carbon bond formed.

4. **Second Nucleophilic Attack**: Since we have excess CH3MgBr, it can also attack the second carbonyl group:
\[ C_6H_5 - C(OH)(C_6H_5) - C(=O) - C_6H_5 + CH_3MgBr \rightarrow C_6H_5 - C(OH)(C_6H_5) - C(OH)(C_6H_5) \]
This results in the formation of another alkoxide.

5. **Hydrolysis**: The next step is hydrolysis, where the alkoxide groups are converted to alcohols by adding water (H2O) and an acid (H+):
\[ C_6H_5 - C(OH)(C_6H_5) - C(OH)(C_6H_5) + H2O \rightarrow C_6H_5 - C(OH)(C_6H_5) - C(OH)(C_6H_5) \]

6. **Final Product**: The final product will have two hydroxyl (OH) groups and two phenyl (C6H5) groups attached to the central carbon chain:
\[ C_6H_5 - C(OH) - C(OH) - C_6H_5 \]

Thus, the final product of the reaction is:
\[ C_6H_5 - C(OH) - C(OH) - C_6H_5 \]