Consider the following reaction `(A)overset((i)O_3)underset((ii)H_2"O"//Zn)rarrCH_3-overset(O)overset(||)C-CH_2-overset(O)overset(||)C-CH_2-overset(O)overset(||)C-CH_3+3HCHO` Compound 'A' will be

Options

A. `CH_3-overset(O)overset(||)C-CH_2-overset(O)overset(||)C-CH_2-overset(CH_2)overset(||)C-CH_3`
B. `CH_3-overset(O)overset(||)C-CH_2-overset(CH_2)overset(||)C-CH_2-overset(O)overset(||)C-CH_3`
C. `CH_3-overset(CH_2)overset(||)C-CH_2-overset(CH_2)overset(||)C-CH_2-underset(CH_3)underset(|)C=CH_2`
D. All of these

Answer

To determine the compound 'A' in the reaction given, we will analyze the ozonolysis process and the products formed. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Reaction
The reaction involves ozonolysis followed by reductive ozonolysis. Ozonolysis is a reaction where alkenes are cleaved to form carbonyl compounds (aldehydes or ketones) upon treatment with ozone (O₃). In the case of reductive ozonolysis, the products are further reduced using zinc (Zn) and water (H₂O).

### Step 2: Identify the Products
The products of the reaction are given as:
- A ketone (from the secondary carbon)
- Three moles of formaldehyde (HCHO)

This indicates that the starting compound 'A' must have multiple double bonds that can be cleaved to yield these products.

### Step 3: Analyze the Structure of the Products
The product structure is:
- CH₃-CO-CH₂-CO-CH₂-CO-CH₃ + 3 HCHO

This suggests that 'A' must have a structure that, when cleaved, results in the formation of the ketone and three aldehyde groups.

### Step 4: Determine the Structure of Compound 'A'
To find 'A', we need to consider the positions of the double bonds in the starting compound. Since we have three moles of HCHO, it indicates that there are three double bonds in the starting compound that will be cleaved.

The structure of 'A' must be an alkene with three double bonds. A possible structure that fits this description is:
- CH₂=CH-CO-CH=CH-CO-CH=CH₂

This structure has three double bonds and upon ozonolysis will yield the specified products.

### Step 5: Verify the Structure
To confirm, we can perform the ozonolysis on the proposed structure:
1. The double bonds will be cleaved, resulting in:
- Two ketones from the secondary carbons
- Three aldehydes from the terminal carbons

Thus, the structure of compound 'A' is consistent with the products formed.

### Conclusion
The compound 'A' is:
- **C₆H₁₄O₃** (specifically, an alkene with three double bonds).