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The IUPAC name of CH3-underset(CONH2)und...

The IUPAC name of `CH_3-underset(CONH_2)underset(|)C=CH-CH_2-underset(OH)underset(|)overset(O)overset(||)C` is

A

4 - carbamoylpent -3- enoic acid

B

4 - amido -4- methyl -but -3- enoic acid

C

3-amido -but-2-enecarboxylic acid

D

4-carboxy -2-methyl - but -2-enamide

Text Solution

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The correct Answer is:
To determine the IUPAC name of the compound `CH_3-CONH_2|C=CH-CH_2|OH||C`, we will follow a systematic approach based on IUPAC naming conventions. ### Step-by-Step Solution: 1. **Identify the Longest Carbon Chain**: - The first step is to identify the longest continuous carbon chain that contains the highest priority functional group. In this case, we have a carboxylic acid (–COOH), an amide (–CONH2), a hydroxyl group (–OH), and a double bond (C=C). - The longest chain consists of 5 carbon atoms. 2. **Number the Carbon Chain**: - Number the carbon chain starting from the end closest to the highest priority functional group. The carboxylic acid has the highest priority, so we start numbering from that end. - The numbering will be as follows: - C1: COOH (carboxylic acid) - C2: CH (attached to the double bond) - C3: CH (part of the double bond) - C4: CH2 (attached to the hydroxyl group) - C5: CH3 (methyl group) 3. **Identify the Functional Groups**: - The functional groups present are: - A carboxylic acid at C1 - A double bond between C2 and C3 - A hydroxyl group at C4 - An amide group at C4 (which will be named as a prefix "carbamoyl"). 4. **Construct the Name**: - The suffix for the carboxylic acid is "oic acid". - The double bond is indicated by "ene", and its position is indicated by the number of the first carbon involved in the double bond (C2). - The amide group at C4 will be indicated as "carbamoyl". - Therefore, the name can be constructed as follows: - Start with the prefix for the longest chain: "pent" (for 5 carbons). - Add the position of the double bond: "3-ene". - Add the prefix for the amide: "4-carbamoyl". - Finally, add the suffix for the carboxylic acid: "oic acid". 5. **Final IUPAC Name**: - Combining all these parts, the final IUPAC name of the compound is **4-carbamoyl-3-pentenoic acid**.
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Knowledge Check

  • The IUPAC name of CH_(3) - underset(OH)underset(|)CH-CH_(2)-underset(OH) underset(|)overset(CH_(3))overset(|)-CH_(3) is

    A
    1,1-dimethyl-1,3-butanediol
    B
    2-methyl-2,4-pentanediol
    C
    4-methyl-2,4-pentanediol
    D
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    A
    1, 1-Dimethyl-1, 3-butanediol and propanetricarbyl amine
    B
    4-Methyl-2, 4-pentanediol and 1, 2, 3- propanetrinitrile
    C
    2-Methyl-2, 4-pentanediol and propane 1, 2, 3- tricarboni trile
    D
    1, 3, 3-Trirnethyl-1, 3-propanediol and 1, 2, 3- tricyano propane
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    A
    1, 1-Dimethylbutane -1, 3-diol
    B
    4-Methylpentane-2, 4-diol
    C
    2-Methylpentane-2, 4-diol
    D
    1, 3, 3-Trimethylpropane-1, 3-diol
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