The reaction of solid `XeF_(2)` with `AsF_(5)` in `1:1` ratio affords

Options

A. `XeF_(4) and AsF_(3)`
B. `XeF_(6) and AsF_(3)`
C. `[XeF]^(+)[AsF_(6)]^(-)`
D. `[Xe_(2)F_(3)]^(+)[AsF_(6)]^(-)`

Answer

To solve the question regarding the reaction of solid \( \text{XeF}_2 \) with \( \text{AsF}_5 \) in a 1:1 ratio, we can follow these steps:

### Step 1: Understanding the Reactants
We have two reactants:
- \( \text{XeF}_2 \) (Xenon difluoride)
- \( \text{AsF}_5 \) (Arsenic pentafluoride)

### Step 2: Analyzing the Reaction Ratio
The question specifies that the reaction occurs in a 1:1 ratio. This means we will consider one mole of \( \text{XeF}_2 \) reacting with one mole of \( \text{AsF}_5 \).

### Step 3: Predicting the Reaction Products
In general, \( \text{XeF}_2 \) can react with \( \text{AsF}_5 \) to form a complex. The typical reaction of \( \text{XeF}_2 \) with \( \text{AsF}_5 \) in a 3:2 ratio produces \( \text{XeF} \) and \( \text{AsF}_6 \), but we need to focus on the 1:1 ratio.

For the 1:1 reaction, the expected product will be:
\[ \text{XeF} + \text{AsF}_6 \]

### Step 4: Writing the Final Reaction Equation
Thus, the reaction can be represented as:
\[ \text{XeF}_2 + \text{AsF}_5 \rightarrow \text{XeF} + \text{AsF}_6 \]

### Step 5: Identifying the Correct Option
From the analysis, the product formed is \( \text{XeF} \) (which is positively charged) and \( \text{AsF}_6 \) (which is negatively charged). Therefore, the correct representation of the product in terms of charge is:
\[ \text{XeF}^+ + \text{AsF}_6^- \]

### Conclusion
The correct answer to the question is that the reaction of solid \( \text{XeF}_2 \) with \( \text{AsF}_5 \) in a 1:1 ratio affords:
\[ \text{XeF}^+ + \text{AsF}_6^- \]