Which of the following will show optical isomerism?

Options

A.
B.
C.
D.

Answer

To determine which of the given compounds shows optical isomerism, we need to follow these steps:

### Step 1: Understand Optical Isomerism
Optical isomerism occurs when a compound can exist in two non-superimposable mirror image forms, known as enantiomers. For a compound to exhibit optical isomerism, it must have a chiral center (usually a carbon atom bonded to four different groups) and must lack a plane of symmetry.

### Step 2: Identify Chiral Centers
Examine each compound to identify if there are any chiral centers. A chiral center is typically a carbon atom that is bonded to four different substituents.

### Step 3: Check for Symmetry
For a compound to be optically active, it must not have a plane of symmetry or a center of symmetry. A plane of symmetry divides a compound into two mirror-image halves, while a center of symmetry means that for any point in the molecule, there is an equivalent point directly opposite it.

### Step 4: Analyze Each Compound
1. **First Compound**: Identify the groups attached to the carbon atom. If it has four different groups, it is chiral and will show optical isomerism.
2. **Second Compound**: Check if there is a plane of symmetry. If the groups are arranged such that you can divide the molecule into two equal halves, it will be optically inactive.
3. **Third Compound**: Similar to the second, check for symmetry.
4. **Fourth Compound**: Again, check for chiral centers and symmetry.

### Step 5: Conclusion
After analyzing all compounds, we conclude that only the first compound shows optical isomerism because it has a chiral carbon and lacks a plane of symmetry.

### Final Answer
The first compound is the only one that shows optical isomerism.

---