In the carbylamine reaction, `R-X` converted `R-Y` via the intermediate `Z, R-X, R-Y and Z`, respectively are

Options

A. `R-NH_(2), R-NC,"carbene"`
B. `R-NH_(2), R-NC," nitrene"`
C. `R-NC, R-NH_(2)," carbene"`
D. `R-OH, R-NC," nitrene"`

Answer

To solve the problem regarding the carbylamine reaction, we need to identify the compounds involved in the reaction and their respective roles. Here’s a step-by-step breakdown of the solution:

### Step 1: Understanding the Carbylamine Reaction
The carbylamine reaction involves a primary amine reacting with chloroform (CHCl₃) in the presence of a base to produce an isocyanate. The general reaction can be summarized as follows:

\[ \text{R-NH}_2 + \text{CHCl}_3 + \text{Base} \rightarrow \text{R-NC} \equiv \text{C} + \text{by-products} \]

### Step 2: Identifying the Reactants
In the reaction:
- **R-X** is the primary amine (R-NH₂).
- **R-Y** is the product, which is an isocyanate (R-NC).
- **Z** is the intermediate formed during the reaction.

### Step 3: Determining the Intermediate (Z)
During the reaction mechanism:
1. Chloroform reacts with the base to form dichlorocarbene (CCl₂), which is the intermediate (Z).
2. The primary amine (R-NH₂) then reacts with this dichlorocarbene to form an intermediate that ultimately leads to the formation of the isocyanate.

Thus, the intermediate **Z** is **CCl₂** (dichlorocarbene).

### Step 4: Summarizing the Compounds
Now we can summarize the compounds:
- **R-X**: R-NH₂ (primary amine)
- **Z**: CCl₂ (dichlorocarbene, the intermediate)
- **R-Y**: R-NC (isocyanate)

### Final Answer
- R-X: R-NH₂ (primary amine)
- Z: CCl₂ (dichlorocarbene)
- R-Y: R-NC (isocyanate)