When an inorganic compound (X) having 3c - 2e as well as 2c - 2e bonds react with ammonia gas at a certain temperature, gives a compound (Y) isostructural with benzene. Compound (X) with ammonia at a high temperature produces a substance (Z). Which option is not correct?

Options

A. (X) is `B_(2)H_(6)`
B. (Z) is known as inorganic graphite
C. (Y) is `B_(3)N_(3)H_(6)`
D. (Z) is soft like graphite

Answer

To solve the problem step by step, let's analyze the information provided in the question and the video transcript.

### Step 1: Identify Compound X
The question states that compound (X) has both 3-center 2-electron (3c-2e) and 2-center 2-electron (2c-2e) bonds. The video identifies compound X as B2H6 (diborane).

**Hint:** Look for compounds that are known to have 3c-2e and 2c-2e bonds.

### Step 2: Reaction of X with Ammonia
When B2H6 reacts with ammonia (NH3) at a certain temperature, it forms a compound (Y) that is isostructural with benzene. The video states that this compound (Y) is B3N3H6, which is known as inorganic benzene.

**Hint:** Understand what is meant by "isostructural" – it means that the compound has a similar structure to benzene.

### Step 3: Identify Compound Y
From the previous step, we conclude that compound Y is B3N3H6, which has a structure similar to benzene, featuring alternating double bonds and a cyclic arrangement.

**Hint:** Compare the structure of B3N3H6 to that of benzene to confirm their isostructural nature.

### Step 4: Reaction of X with Ammonia at High Temperature
The video explains that when B2H6 reacts with ammonia at high temperatures, it produces a substance (Z). This substance is identified as BN (boron nitride), which is referred to as inorganic graphite.

**Hint:** Consider the effect of temperature on chemical reactions and how it can lead to the formation of different products.

### Step 5: Analyze the Options
Now we need to evaluate the options given in the question:

1. **Option 1:** X is B2H6 - This is correct.
2. **Option 2:** Z is known as inorganic graphite - This is correct.
3. **Option 3:** Y is B3N3H6 - This is correct.
4. **Option 4:** Z is soft like graphite - This is incorrect because BN is a hard material, not soft.

**Hint:** Carefully read each option and compare it with the information derived from the previous steps to determine which statement is not correct.

### Conclusion
The option that is not correct is **Option 4**, which states that Z is soft like graphite. In reality, Z (BN) is a hard substance.

### Final Answer
**The incorrect option is Option 4: Z is soft like graphite.**