If number of lone pairs on central atom in `XeF_(2), XeF_(4) and XeF_(6)` are x, y, z. What is the sum of `x+y+z` here?

Answer

To solve the problem, we need to determine the number of lone pairs on the central atom (xenon, Xe) in the molecules XeF2, XeF4, and XeF6.

### Step 1: Determine the number of valence electrons for xenon (Xe)
Xenon is in group 18 of the periodic table, which means it has 8 valence electrons.

### Step 2: Analyze XeF2
- **XeF2**:
- Xenon is bonded to 2 fluorine atoms.
- Each fluorine atom forms a single bond with xenon, using 2 of xenon's valence electrons (1 for each bond).
- Total electrons used in bonding = 2 (1 for each bond).
- Remaining valence electrons = 8 (total) - 2 (bonding) = 6.
- These remaining 6 electrons will form 3 lone pairs.

Thus, for XeF2, the number of lone pairs (x) = 3.

### Step 3: Analyze XeF4
- **XeF4**:
- Xenon is bonded to 4 fluorine atoms.
- Each fluorine atom forms a single bond with xenon, using 4 of xenon's valence electrons (1 for each bond).
- Total electrons used in bonding = 4.
- Remaining valence electrons = 8 (total) - 4 (bonding) = 4.
- These remaining 4 electrons will form 2 lone pairs.

Thus, for XeF4, the number of lone pairs (y) = 2.

### Step 4: Analyze XeF6
- **XeF6**:
- Xenon is bonded to 6 fluorine atoms.
- Each fluorine atom forms a single bond with xenon, using 6 of xenon's valence electrons (1 for each bond).
- Total electrons used in bonding = 6.
- Remaining valence electrons = 8 (total) - 6 (bonding) = 2.
- These remaining 2 electrons will form 1 lone pair.

Thus, for XeF6, the number of lone pairs (z) = 1.

### Step 5: Calculate the sum of lone pairs
Now, we can find the sum of the lone pairs:
- x + y + z = 3 (from XeF2) + 2 (from XeF4) + 1 (from XeF6) = 6.

### Final Answer
The sum of x + y + z = 6.

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