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In a first order reaction, the concentra...

In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is -

A

30 mintures

B

15 minutes

C

7.5 minutes

D

60 minutes

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The correct Answer is:
To solve the problem, we need to determine the time taken for the concentration of a reactant in a first-order reaction to change from 0.1 M to 0.025 M. We know that the concentration of the reactant decreases from 0.8 M to 0.4 M in 15 minutes. ### Step-by-Step Solution: 1. **Understanding First-Order Reactions**: In a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant. The half-life (T_half) of a first-order reaction is constant and does not depend on the initial concentration. 2. **Calculate the Half-Life (T_half)**: From the information given, the concentration decreases from 0.8 M to 0.4 M in 15 minutes. This represents one half-life because 0.4 M is half of 0.8 M. \[ T_{half} = 15 \text{ minutes} \] 3. **Determine the Time for the Next Half-Life**: Now, we need to find the time taken for the concentration to change from 0.1 M to 0.025 M. - Starting from 0.1 M, the first half-life will take it to 0.05 M (15 minutes). - The next half-life will take it from 0.05 M to 0.025 M (another 15 minutes). 4. **Calculate Total Time**: Therefore, the total time taken for the concentration to change from 0.1 M to 0.025 M is: \[ \text{Total Time} = 15 \text{ minutes} + 15 \text{ minutes} = 30 \text{ minutes} \] ### Final Answer: The time taken for the concentration to change from 0.1 M to 0.025 M is **30 minutes**. ---
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