In the sequence of reactions
`C_(6)H_(5)Broverset(Mg)underset("ether")rarr (X) overset((i)CO_(2))underset((iii)H_(3)O^(+))rarr(Y)` the product (Y) is

Options

A. biphenyl
B. m - bromobenzoic acid
C. benzoic acid
D. benzyl alcohol

Answer

To solve the problem, we will go through the sequence of reactions step by step.

### Step 1: Formation of Grignard Reagent
The first step involves the reaction of phenyl bromide (C₆H₅Br) with magnesium (Mg) in the presence of ether. This reaction produces a Grignard reagent.

**Reaction:**
\[ C₆H₅Br + Mg \xrightarrow{\text{ether}} C₆H₅MgBr \]

Here, C₆H₅MgBr is the Grignard reagent (denoted as X).

### Step 2: Reaction with Carbon Dioxide
Next, the Grignard reagent (C₆H₅MgBr) reacts with carbon dioxide (CO₂). The nucleophilic carbon of the Grignard reagent attacks the electrophilic carbon of CO₂.

**Reaction:**
\[ C₆H₅MgBr + CO₂ \rightarrow C₆H₅C(=O)O^{-}MgBr^{+} \]

This intermediate product is a carboxylate ion (C₆H₅C(=O)O⁻) with magnesium bromide (MgBr⁺).

### Step 3: Hydrolysis
The final step involves the hydrolysis of the carboxylate ion in the presence of an acid (H₃O⁺). This hydrolysis converts the carboxylate ion into a carboxylic acid.

**Reaction:**
\[ C₆H₅C(=O)O^{-}MgBr^{+} + H₃O^{+} \rightarrow C₆H₅C(=O)OH + MgBr^{+} + H₂O \]

The product of this reaction is benzoic acid (C₆H₅C(=O)OH), denoted as Y.

### Final Answer
The product (Y) is **benzoic acid (C₆H₅COOH)**.

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