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Give the produst when an excess of PhMgB...

Give the produst when an excess of `PhMgBr//H^(+)` reacts with dimethyl carbonate `(CH_(3)OCOOCH_(3))`?

A

`CH_(3)-overset(OH)overset("| ")"CH"-Ph`

B

`CH_(3)-overset(OH)overset("| ")underset(Ph)underset("| ")"C "-PH`

C

`Ph-overset(OH)overset("| ")underset(Ph)underset("| ")"C "-Ph`

D

`CH_(3)-overset(O)overset(||)C-Ph`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the product formed when an excess of phenylmagnesium bromide (PhMgBr) reacts with dimethyl carbonate (CH₃OCOOCH₃), we can follow these steps: ### Step 1: Identify the Reactants - The reactants are phenylmagnesium bromide (PhMgBr) and dimethyl carbonate (CH₃OCOOCH₃). - PhMgBr is a Grignard reagent, where Ph⁻ acts as a nucleophile. ### Step 2: Nucleophilic Attack - The nucleophile (Ph⁻) will attack the carbonyl carbon (C=O) of dimethyl carbonate. - The structure of dimethyl carbonate is: ``` O || CH₃-O-C | O / \ CH₃ CH₃ ``` - The carbonyl carbon is electrophilic and will be attacked by the nucleophile. ### Step 3: Formation of the Intermediate - When Ph⁻ attacks the carbonyl carbon, it forms a tetrahedral intermediate: ``` O | CH₃-O-C | O / \ CH₃ Ph ``` - This intermediate has a negative charge on the oxygen atom. ### Step 4: Protonation - The negatively charged oxygen can be protonated by the H⁺ from the reaction medium. - This results in the formation of an alcohol: ``` O | CH₃-O-C | O / \ CH₃ Ph ``` ### Step 5: Repeat the Reaction - Since we have excess PhMgBr, the Ph⁻ can attack again. - The process will repeat, leading to further nucleophilic attacks on the carbonyl carbon. ### Step 6: Final Product Formation - After multiple attacks, we will end up with a compound where three phenyl groups are attached to the carbon, and the original dimethyl carbonate structure is transformed. - The final product will be triphenylmethanol (Ph₃C-OH). ### Final Product The final product of the reaction is: - Triphenylmethanol (Ph₃C-OH). ### Summary of the Reaction 1. Ph⁻ attacks the carbonyl carbon of dimethyl carbonate. 2. Formation of a tetrahedral intermediate. 3. Protonation of the intermediate to form a phenolic compound. 4. Repeated nucleophilic attacks lead to the formation of triphenylmethanol.
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