The heating of oxime of acetone in presence of conc. `H_(2)SO_(4)` to form N - methyl ethanamide is called

Options

A. Bayer - Villger rearrangement
B. Beckmann rearrangement
C. Wolf - rearrangement
D. Hoffmann reaction

Answer

To solve the question regarding the heating of oxime of acetone in the presence of concentrated sulfuric acid to form N-methyl ethanamide, we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is the oxime of acetone, which can be represented as CH3C(=NOH)CH3. This compound has a hydroxylamine (-NOH) group attached to the carbonyl carbon of acetone.

2. **Heating with Concentrated H2SO4**:
- When oxime of acetone is heated with concentrated sulfuric acid (H2SO4), it undergoes dehydration. The concentrated sulfuric acid acts as a dehydrating agent, removing water (H2O) from the oxime.

3. **Formation of an Intermediate**:
- The dehydration leads to the formation of an intermediate compound, which is an imine (or an oxime derivative). The reaction can be represented as:
\[ CH3C(=NOH)CH3 \xrightarrow{H2SO4} CH3C=N-CH3 + H2O \]

4. **Rearrangement to N-Methyl Ethanamide**:
- The imine can then undergo rearrangement. In this case, the rearrangement involves the migration of the methyl group and the formation of N-methyl ethanamide (CH3C(=O)NHCH3). The reaction can be summarized as:
\[ CH3C=N-CH3 \rightarrow CH3C(=O)NHCH3 \]

5. **Conclusion**:
- The overall process is a rearrangement reaction where the oxime of acetone is converted into N-methyl ethanamide through dehydration and subsequent rearrangement.

### Final Answer:
The heating of oxime of acetone in the presence of concentrated H2SO4 to form N-methyl ethanamide is called **rearrangement reaction**.