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If K(1) and K(2) are respective equilib...

If `K_(1)` and `K_(2)` are respective equilibrium constants for two reactions `:`
`XeF_(6)(g) +H_(2)O hArr XeOF_(4)(g) +2HF_(g)`
`XeO_(4)(g)+XeF_(6)(g)hArr XeOF_(4)(g)+XeO_(3)F_(2)(g)`
Then equilibrium constant for the reaction
`XeO_(4)(g)+2HF(g) hArr XeO_(3)F_(2)(g)+H_(2)O(g)` will be

A

`(K_(1))/(K_(2)^(2))`

B

`K_(1)-K_(2)`

C

`(K_(1))/(K_(2))`

D

`(K_(2))/(K_(1))`

Text Solution

Verified by Experts

The correct Answer is:
D
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