What are the products formed in the reaction of xenon hexa fluoride with silica?

Options

A. `XeSiO_(4)+HF`
B. `XeF_(2)+SiF_(4)`
C. `XeO_(3)+SiF_(4)`
D. `XeOF_(4)+SiF_(4)`

Answer

To solve the question regarding the products formed when xenon hexafluoride (XeF6) reacts with silica (SiO2), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are xenon hexafluoride (XeF6) and silica (SiO2).

### Step 2: Determine the Oxidation States
- For xenon in XeF6:
- Fluorine has an oxidation state of -1.
- Therefore, in XeF6, the oxidation state of xenon can be calculated as follows:
\[ x + 6(-1) = 0 \implies x - 6 = 0 \implies x = +6 \]
- Thus, the oxidation state of xenon in XeF6 is +6.

- For silicon in SiO2:
- Oxygen has an oxidation state of -2, and there are two oxygen atoms:
\[ x + 2(-2) = 0 \implies x - 4 = 0 \implies x = +4 \]
- Therefore, the oxidation state of silicon in SiO2 is +4.

### Step 3: Analyze the Reaction
When XeF6 reacts with SiO2, the oxidation states of xenon and silicon do not change. This means that xenon remains in the +6 oxidation state and silicon remains in the +4 oxidation state.

### Step 4: Write the Products
The products formed from the reaction of xenon hexafluoride with silica are:
1. Xenon oxyfluoride (XeOF4)
2. Silicon tetrafluoride (SiF4)

The balanced reaction can be represented as:
\[ \text{XeF}_6 + \text{SiO}_2 \rightarrow \text{XeOF}_4 + \text{SiF}_4 \]

### Step 5: Conclusion
The products formed in the reaction of xenon hexafluoride with silica are xenon oxyfluoride (XeOF4) and silicon tetrafluoride (SiF4).

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