How many O - atoms are present in Equanil.

Answer

To determine how many oxygen atoms are present in Equanil (also known as Maprotiline), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Chemical Structure**:
- Equanil (Maprotiline) has a specific chemical structure that includes various functional groups. To find the number of oxygen atoms, we need to analyze this structure.

2. **Draw the Structure**:
- The chemical structure of Maprotiline can be represented as NH2-CO-OH-CH2-CH2-CH3. This indicates the presence of different groups including an amine (NH2), a carbonyl (C=O), and a hydroxyl (OH) group.

3. **Identify the Oxygen Atoms**:
- In the structure, we can identify the following oxygen-containing groups:
- One from the carbonyl group (C=O)
- One from the hydroxyl group (OH)
- Additionally, if there are any ether or ester groups, those would contribute more oxygen atoms.

4. **Count the Oxygen Atoms**:
- From the identified groups:
- Carbonyl (C=O) contributes 1 oxygen atom.
- Hydroxyl (OH) contributes 1 oxygen atom.
- If there are any other functional groups that contain oxygen, we need to include those as well.

5. **Total Count**:
- After counting all the oxygen atoms from the identified groups, we find that there are 4 oxygen atoms in total in the structure of Equanil.

### Final Answer:
- Therefore, the total number of oxygen atoms present in Equanil is **4**.

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