The IUPAC name of the given structure `CH_(3)-overset(O)overset(||)C-overset(Br)overset(|)CH-underset(I)underset(|)CH-COOH` is-

Options

A. 4 - keto -3- bromo -2- iodopentanoic acid
B. 2 - iodo -3- bromo -4- keto - pentanoic acid
C. 3 - bromo -2- iodo -4- ketopentanoic acid
D. 4 - carboxy -3- bromo -4- iodopentanoic acid

Answer

To determine the IUPAC name of the given structure `CH₃-CO-C(Br)-CH(I)-CH-COOH`, we will follow these steps:

### Step 1: Identify the Functional Groups
The structure contains:
- A carboxylic acid group (-COOH)
- A bromo substituent (Br)
- An iodo substituent (I)
- A ketone group (C=O)

### Step 2: Determine the Parent Chain
According to IUPAC nomenclature rules, the carboxylic acid has the highest priority. Therefore, we will select the longest carbon chain that includes the carboxylic acid.

Counting the carbons:
1. Start from the carboxylic acid carbon and count towards the other end.
2. The longest chain contains 5 carbons.

Thus, the parent chain is pentanoic acid.

### Step 3: Number the Carbon Chain
Number the carbon chain starting from the end closest to the carboxylic acid:
1. COOH (C1)
2. C2 (next carbon)
3. C3 (next carbon with Br)
4. C4 (next carbon with I)
5. C5 (next carbon with C=O)

### Step 4: Identify and Name the Substituents
- The bromo substituent (Br) is on carbon 3.
- The iodo substituent (I) is on carbon 2.
- The ketone group (C=O) is on carbon 4.

### Step 5: Assemble the IUPAC Name
According to the IUPAC naming conventions, the substituents are listed in alphabetical order, regardless of their position numbers:
1. Bromo (Br) comes before Iodo (I).
2. Therefore, the name will include:
- 3-bromo
- 2-iodo
- 4-keto
- pentanoic acid

Combining these, the full IUPAC name is:
**3-bromo-2-iodo-4-ketopentanoic acid**

### Final Answer
The IUPAC name of the given structure is **3-bromo-2-iodo-4-ketopentanoic acid**.

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