How many of these elements have more first ionization energy then boron `Li, Be, C, N, O, F, Ne`

Answer

To determine how many elements from the list `Li, Be, C, N, O, F, Ne` have a first ionization energy greater than that of boron (B), we can follow these steps:

### Step 1: Understand Ionization Energy
Ionization energy is the energy required to remove an electron from an atom in its gaseous state. Generally, ionization energy increases across a period from left to right due to increasing nuclear charge and decreasing atomic size.

### Step 2: List the Elements and Their Ionization Energies
We need to compare the first ionization energies of the elements with that of boron. The approximate first ionization energies (in eV) for the elements are:

- Li (Lithium): 5.39 eV
- Be (Beryllium): 9.32 eV
- B (Boron): 8.30 eV
- C (Carbon): 11.26 eV
- N (Nitrogen): 14.53 eV
- O (Oxygen): 13.62 eV
- F (Fluorine): 17.42 eV
- Ne (Neon): 21.56 eV

### Step 3: Compare Each Element's Ionization Energy with Boron
Now, we will compare the ionization energies of each element with that of boron:

- **Li**: 5.39 eV (less than B)
- **Be**: 9.32 eV (greater than B)
- **C**: 11.26 eV (greater than B)
- **N**: 14.53 eV (greater than B)
- **O**: 13.62 eV (greater than B)
- **F**: 17.42 eV (greater than B)
- **Ne**: 21.56 eV (greater than B)

### Step 4: Count the Elements with Higher Ionization Energy
From the comparison:
- **Elements with higher ionization energy than boron**: Be, C, N, O, F, Ne

Counting these, we find there are **6 elements** (Be, C, N, O, F, Ne) that have a first ionization energy greater than that of boron.

### Final Answer
Thus, the total number of elements that have a first ionization energy greater than boron is **6**.

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