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Calculate the uncertainty in velocity if...

Calculate the uncertainty in velocity if the uncertainty in the position of a moving bullet of mass 10 gm is `10^(-5)m`.

A

`5.2xx10^(-28)m//sec`

B

`3.0xx10^(-28)m//sec`

C

`5.2xx10^(-22)m//sec`

D

`3xx10^(-22)m//sec`

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the uncertainty in velocity (\( \Delta v \)) of a moving bullet given the uncertainty in position (\( \Delta x \)), we can use Heisenberg's uncertainty principle. The principle states that the product of the uncertainties in position and momentum is always greater than or equal to \( \frac{h}{4\pi} \), where \( h \) is Planck's constant. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Uncertainty in position (\( \Delta x \)) = \( 10^{-5} \, m \) - Mass of the bullet (\( m \)) = \( 10 \, gm = 10 \times 10^{-3} \, kg = 0.01 \, kg \) - Planck's constant (\( h \)) = \( 6.626 \times 10^{-34} \, Js \) 2. **Use Heisenberg's Uncertainty Principle:** The principle can be expressed as: \[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \] where \( \Delta p \) is the uncertainty in momentum. 3. **Relate Momentum to Velocity:** The momentum (\( p \)) is given by: \[ p = m \cdot v \] Therefore, the uncertainty in momentum (\( \Delta p \)) can be expressed as: \[ \Delta p = m \cdot \Delta v \] Substituting this into the uncertainty principle gives: \[ \Delta x \cdot (m \cdot \Delta v) \geq \frac{h}{4\pi} \] 4. **Rearranging the Equation:** We can rearrange the equation to solve for \( \Delta v \): \[ \Delta v \geq \frac{h}{4\pi \Delta x \cdot m} \] 5. **Substituting the Known Values:** Plugging in the values: \[ \Delta v \geq \frac{6.626 \times 10^{-34}}{4 \cdot \pi \cdot (10^{-5}) \cdot (0.01)} \] 6. **Calculating the Denominator:** First, calculate \( 4 \cdot \pi \cdot (10^{-5}) \cdot (0.01) \): \[ 4 \cdot \pi \approx 12.566 \] \[ 12.566 \cdot 10^{-7} = 1.2566 \times 10^{-6} \] 7. **Final Calculation:** Now calculate \( \Delta v \): \[ \Delta v \geq \frac{6.626 \times 10^{-34}}{1.2566 \times 10^{-6}} \approx 5.28 \times 10^{-28} \, m/s \] ### Conclusion: The uncertainty in velocity (\( \Delta v \)) of the moving bullet is approximately: \[ \Delta v \approx 5.28 \times 10^{-28} \, m/s \]
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