Products of the reaction which is given below will be
`CH_(3)-underset(CH_(3))underset("| ")"C "=CH-CH_(3)overset((i)OsO_(4)(ii)aq. NaHSO_(3))underset((iii)NalO_(4))rarr`

Options

A. Vic diol
B. Vic dicarbonyl compound
C. `CH_(3)-overset(O)overset(||)C-CH_(3) and CH_(3)-CHO`
D. `CH_(3)-overset(O)overset(||)C-CH_(3) and CH_(3)-COOH`

Answer

To solve the given problem, we need to analyze the reaction step by step. The reaction involves an alkene and proceeds through multiple steps involving different reagents.

### Step 1: Identify the starting compound
The starting compound is:
\[ \text{CH}_3-\text{C}(\text{CH}_3)=\text{CH}-\text{CH}_3 \]
This compound is an alkene.

### Step 2: Reaction with OsO4
The first reagent is OsO4 (osmium tetroxide). OsO4 is known for its ability to add hydroxyl groups (OH) across the double bond of alkenes, resulting in a diol (glycol).

When the alkene reacts with OsO4, we get a diol:
\[ \text{CH}_3-\text{C}(\text{CH}_3)(\text{OH})-\text{CH}(\text{OH})-\text{CH}_3 \]
This can be represented as:
\[ \text{CH}_3-\text{C}(\text{OH})-\text{C}(\text{OH})-\text{CH}_3 \]

### Step 3: Reaction with NaHSO3
The next reagent is aqueous NaHSO3 (sodium bisulfite), which is used to stabilize the diol formed in the previous step. The product remains a diol:
\[ \text{CH}_3-\text{C}(\text{OH})-\text{C}(\text{OH})-\text{CH}_3 \]

### Step 4: Reaction with NaIO4
The final reagent is NaIO4 (sodium periodate), which is used to cleave the diol. This reagent cleaves the carbon-carbon bond between the two carbons that are bonded to hydroxyl groups, resulting in the formation of carbonyl compounds (aldehydes and/or ketones).

After the cleavage, we will get:
1. Acetone (from the central carbon)
2. Acetaldehyde (from the terminal carbon)

The products can be represented as:
\[ \text{CH}_3-\text{C}(=O)-\text{CH}_3 \quad (\text{Acetone}) \]
\[ \text{CH}_3-\text{C}(=O)-\text{H} \quad (\text{Acetaldehyde}) \]

### Final Products
Thus, the final products of the reaction are:
1. Acetone (\( \text{CH}_3\text{COCH}_3 \))
2. Acetaldehyde (\( \text{CH}_3\text{CHO} \))

### Conclusion
The correct answer is:
- Acetone and Acetaldehyde.

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