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In the reaction sequence C(6)H(5)-unders...

In the reaction sequence `C_(6)H_(5)-underset(O)underset(||)C-CH_(3)overset(NH_(2)OH//overset(o+)H)rarr(A)overset(P_(2)O_(5))rarr [X]`
[X] will be

A

`{:(C_(6)H_(5)-C-CH_(3)),(" ||"),(" "N-OH):}`

B

`CH_(3)COOH`

C

`C_(6)H_(5)-NH_(2)`

D

`CH_(3)-CO-NH-C_(6)H_(5)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given reaction sequence, we need to analyze each step carefully. The initial compound is a phenyl ketone, and we are reacting it with hydroxylamine (NH2OH) followed by an acid and then phosphorus pentoxide (P2O5). Let's break it down step by step. ### Step 1: Identify the Initial Compound The initial compound is `C6H5-CO-CH3`, which is acetophenone (phenyl methyl ketone). ### Step 2: Reaction with Hydroxylamine When acetophenone reacts with hydroxylamine (NH2OH), it forms an oxime. The reaction can be represented as follows: - **Reaction**: \[ C6H5-CO-CH3 + NH2OH \rightarrow C6H5-C(=NOH)-CH3 + H2O \] - **Product**: The product is an oxime, `C6H5-C(=NOH)-CH3`. ### Step 3: Protonation of the Oxime Next, the oxime is treated with an acid (H+). The hydroxyl group (OH) of the oxime gets protonated, making it a better leaving group: - **Reaction**: \[ C6H5-C(=NOH)-CH3 + H^+ \rightarrow C6H5-C(=N^+OH)-CH3 \] - **Intermediate**: This leads to a positively charged intermediate. ### Step 4: Elimination of Water In the presence of the acid, the oxime can undergo dehydration (loss of water), leading to the formation of an imine: - **Reaction**: \[ C6H5-C(=N^+OH)-CH3 \rightarrow C6H5-C(=N)-CH3 + H2O \] - **Product**: The product is an imine, `C6H5-C(=N)-CH3`. ### Step 5: Reaction with P2O5 Finally, when the imine is treated with phosphorus pentoxide (P2O5), which is a dehydrating agent, it will not further change the structure significantly because the imine is already dehydrated: - **Reaction**: \[ C6H5-C(=N)-CH3 + P2O5 \rightarrow C6H5-C(=N)-CH3 \] - **Final Product**: The final product remains the same, which is `C6H5-C(=N)-CH3`. ### Conclusion Thus, the final product [X] after the entire reaction sequence is: \[ \text{[X] = } C6H5-C(=N)-CH3 \]
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निम्न अभिक्रिया अनुक्रम में C_6H_5-underset(O)underset(||)(C)-CH_3overset(NH_2OH//overset(o+)(H))(rarr)(A) overset(P_2O_5)(rarr)[X] [X] होगा:

In the given reaction sequence C_(6)H_(5)CHO underset(H^(o+), Delta)overset(H_(2)N-OH)rarr A overset(P_(2)O_(5))rarrB A and B respectively are:

Knowledge Check

  • In the reactin sequence C_(6)H_(5)-underset(O)underset(||)C-CH_(3)overset(NH_(2)OH//H^(o+))rarr[X]overset(PCl_(5))rarr[Y],[Y] will be :

    A
    `C_(6)H_(5)-overset(O)overset(||)C-NHCH_(3)`
    B
    `CH_(3)-overset(O)overset(||)C-NH-C_(6)H_(5)`
    C
    `C_(6)H_(5)-CH_(2)-Coverset(O)overset(||)C-NH_(2)`
    D
    Mixture of (a) and (b)
  • In the given reaction [X] will be : C_(6)H_(5)-underset(O)underset(||)C-Hoverset(NH_(2)OH//H^(o+))rarr [X]

    A
    only syn oxime
    B
    only anti oxime
    C
    mixture of syn and anti oxime
    D
    secondary amide
  • In the given reaction C_6H_5-underset(O)underset(||)C-CH_3overset(NH_2OH//H^(o+))rarr[X]overset(Na//C_2H_5OH)rarr[Y] [Y] will be

    A
    `C_6H_5-underset(CH_3)underset(|)(CH)-NH_2`
    B
    `C_6H_5-underset(CH_3)underset(|)(CH)-NH-CH_3`
    C
    `C_6H_5-overset(O)overset(||)C-NH-CH_3`
    D
    `CH_3-overset(O)overset(||)C-NH-C_6H_5`
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