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An alloy of Pb-Ag weighing 1.08g was dis...

An alloy of Pb-Ag weighing `1.08g` was dissolved in dilute `HNO_(3)` and the volume made to 100 mL.A ? Silver electrode was dipped in the solution and the emf of the cell dipped in the solution and the emf of the cell set-up as `Pt(s),H_(2)(g)|H^(+)(1M)||Ag^(+)(aq.)|Ag(s)` was `0.62 V` . If `E_("cell")^(@)` is `0.80 V`, what is the percentage of Ag in the alloy ? (At `25^(@)C, RT//F=0.06`)

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An alloy of Pb-Ag weighing 54 mg was dissolved in desired amount of HNO_(3) & volume was made upto 500ml . An Ag electrode was dipped in solution and then connected to standard hydrogen electrode anode. Then calculate % of Ag in alloy. Given: E_(cell) = 0.5V, E_(Ag^(+)//Ag)^(@) = 0.8V (2.303RT)/(F) = 0.06

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