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Arrange the following carbocations in or...

Arrange the following carbocations in order of stability
`{:("benzyl allyl methyl vinyl"),(" I II III IV"):}`

A

`IV gt III gt II gt I`

B

`I gt II gt III gt IV`

C

`II gt IV gt III gt I`

D

`III gt II gt I gt IV`

Text Solution

AI Generated Solution

The correct Answer is:
To arrange the given carbocations (benzyl, allyl, methyl, and vinyl) in order of stability, we can analyze each carbocation based on resonance and hybridization effects. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Carbocations - **Benzyl Carbocation (I)**: This has a positive charge on a carbon that is directly attached to a benzene ring. - **Allyl Carbocation (II)**: This has a positive charge on a carbon that is adjacent to a carbon-carbon double bond. - **Methyl Carbocation (III)**: This has a positive charge on a carbon that is attached to three hydrogens (no resonance). - **Vinyl Carbocation (IV)**: This has a positive charge on a carbon that is part of a double bond (sp-hybridized). ### Step 2: Analyze Resonance Stabilization - **Benzyl Carbocation**: The positive charge can be delocalized over the benzene ring through resonance. This results in multiple resonance structures, enhancing stability. - **Allyl Carbocation**: The positive charge can also be delocalized through resonance with the adjacent double bond, but it has fewer resonance structures compared to the benzyl carbocation. - **Methyl Carbocation**: This carbocation has no resonance stabilization; it is a simple structure with a positive charge on a carbon. - **Vinyl Carbocation**: Similar to the methyl carbocation, it has no resonance stabilization. Additionally, the carbon bearing the positive charge is sp-hybridized, which is less stable due to higher s-character (50%). ### Step 3: Compare Stability - **Benzyl (I)**: Most stable due to extensive resonance. - **Allyl (II)**: More stable than methyl and vinyl due to resonance but less stable than benzyl. - **Methyl (III)**: More stable than vinyl due to lower s-character. - **Vinyl (IV)**: Least stable due to lack of resonance and high s-character. ### Step 4: Order of Stability Based on the analysis: 1. **Benzyl (I)** - Most stable 2. **Allyl (II)** 3. **Methyl (III)** 4. **Vinyl (IV)** - Least stable Thus, the order of stability of the carbocations is: **Benzyl > Allyl > Methyl > Vinyl** ### Final Answer The correct order of stability is: **I > II > III > IV** ---
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