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A solution containing 12.5 g of non - el...

A solution containing 12.5 g of non - electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of the substance. Elevation constant `(K_(b))` for water `"0.52 K kg mol"^(-1)`?

A

53

B

65

C

84

D

79

Text Solution

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The correct Answer is:
To calculate the molar mass of the non-electrolyte substance based on the given data, we can follow these steps: ### Step 1: Understand the given data - Mass of the solute (non-electrolyte substance) = 12.5 g - Mass of the solvent (water) = 175 g - Boiling point elevation (ΔT) = 0.70 K - Boiling point elevation constant (K_b) for water = 0.52 K kg mol⁻¹ ### Step 2: Use the formula for boiling point elevation The formula for boiling point elevation is given by: \[ \Delta T = K_b \times m \] where: - \( \Delta T \) is the boiling point elevation, - \( K_b \) is the boiling point elevation constant, - \( m \) is the molality of the solution. ### Step 3: Rearrange the formula to find molality Rearranging the formula to find molality (m): \[ m = \frac{\Delta T}{K_b} \] ### Step 4: Substitute the known values Substituting the known values into the equation: \[ m = \frac{0.70 \, \text{K}}{0.52 \, \text{K kg mol}^{-1}} \approx 1.346 \, \text{mol/kg} \] ### Step 5: Calculate the number of moles of solute Molality (m) is defined as the number of moles of solute per kilogram of solvent. Thus: \[ m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} \] Converting the mass of solvent from grams to kilograms: \[ \text{mass of solvent} = 175 \, \text{g} = 0.175 \, \text{kg} \] Now, we can express the number of moles of solute: \[ \text{moles of solute} = m \times \text{mass of solvent in kg} = 1.346 \, \text{mol/kg} \times 0.175 \, \text{kg} \approx 0.2356 \, \text{mol} \] ### Step 6: Calculate the molar mass of the solute Molar mass (M) is defined as the mass of the solute divided by the number of moles of solute: \[ M = \frac{\text{mass of solute}}{\text{moles of solute}} = \frac{12.5 \, \text{g}}{0.2356 \, \text{mol}} \approx 53.06 \, \text{g/mol} \] ### Step 7: Final result The molar mass of the non-electrolyte substance is approximately 53.06 g/mol. ### Summary The calculated molar mass of the substance is approximately 53 g/mol, which corresponds to the closest integer option available. ---
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