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Arrange the following compounds in decre...

Arrange the following compounds in decreasing order of their boiling points
(i) `CH_(3)Cl`
(ii) `CH_(3)CH_(2)Cl`
(iii) `CH_(3)CH_(2)CH_(2)Cl`
(iv) `CH_(3)CH_(2)CH_(2)CH_(2)Cl`

A

`(iii) gt(iv) gt (i) gt (ii)`

B

`(iv) gt (iii) gt (ii) gt (i)`

C

`(i) gt (iii) gt (ii) gt (iv)`

D

`(i) gt (ii) gt (iii) gt (iv)`

Text Solution

AI Generated Solution

The correct Answer is:
To arrange the compounds `CH₃Cl`, `CH₃CH₂Cl`, `CH₃CH₂CH₂Cl`, and `CH₃CH₂CH₂CH₂Cl` in decreasing order of their boiling points, we will follow these steps: ### Step 1: Identify the Compounds The compounds are: 1. `CH₃Cl` (Methyl chloride) 2. `CH₃CH₂Cl` (Ethyl chloride) 3. `CH₃CH₂CH₂Cl` (Propyl chloride) 4. `CH₃CH₂CH₂CH₂Cl` (Butyl chloride) ### Step 2: Consider the Factors Affecting Boiling Points The boiling point of a compound is influenced by: - Molecular weight - Type of substituents (in this case, they all have Cl) - Branching (none of these compounds are branched) ### Step 3: Analyze Molecular Weights The molecular weights of the compounds can be calculated as follows: - `CH₃Cl`: 12 (C) + 3 (H) + 35.5 (Cl) = 50.5 g/mol - `CH₃CH₂Cl`: 12 (C) + 2*1 (H) + 12 (C) + 35.5 (Cl) = 64.5 g/mol - `CH₃CH₂CH₂Cl`: 12 (C) + 3*1 (H) + 12 (C) + 12 (C) + 35.5 (Cl) = 78.5 g/mol - `CH₃CH₂CH₂CH₂Cl`: 12 (C) + 4*1 (H) + 12 (C) + 12 (C) + 35.5 (Cl) = 92.5 g/mol ### Step 4: Compare the Molecular Weights From the calculations above, we can see that: - `CH₃Cl` has the lowest molecular weight (50.5 g/mol) - `CH₃CH₂Cl` has a higher molecular weight (64.5 g/mol) - `CH₃CH₂CH₂Cl` has an even higher molecular weight (78.5 g/mol) - `CH₃CH₂CH₂CH₂Cl` has the highest molecular weight (92.5 g/mol) ### Step 5: Arrange in Decreasing Order of Boiling Points Since molecular weight is a significant factor affecting boiling points, we can arrange the compounds in decreasing order of their boiling points based on their molecular weights: 1. `CH₃CH₂CH₂CH₂Cl` (Butyl chloride) - highest boiling point 2. `CH₃CH₂CH₂Cl` (Propyl chloride) 3. `CH₃CH₂Cl` (Ethyl chloride) 4. `CH₃Cl` (Methyl chloride) - lowest boiling point ### Final Answer The order of the compounds in decreasing order of their boiling points is: `CH₃CH₂CH₂CH₂Cl` > `CH₃CH₂CH₂Cl` > `CH₃CH₂Cl` > `CH₃Cl`
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