No. of `alpha-H` atoms in the product (alkene) formed when `(CH_(3))_(3)C CH(OH)CH_(3)` reacts with conc. `H_(2)SO_(4)`

Answer

To determine the number of alpha-hydrogen atoms in the product (alkene) formed when (CH₃)₃C-CH(OH)CH₃ reacts with concentrated H₂SO₄, we can follow these steps:

### Step 1: Identify the structure of the starting compound
The compound (CH₃)₃C-CH(OH)CH₃ can be drawn as follows:
- The central carbon (C) is connected to a hydroxyl group (OH) and two methyl groups (CH₃).
- The structure can be represented as:
```
CH₃
|
CH₃-C-CH(OH)-CH₃
|
CH₃
```

### Step 2: Reaction with concentrated H₂SO₄
When (CH₃)₃C-CH(OH)CH₃ reacts with concentrated sulfuric acid (H₂SO₄), the hydroxyl group (OH) is protonated to form a better leaving group (water, H₂O). This leads to the formation of a carbocation.

### Step 3: Formation of the carbocation
The protonation of the hydroxyl group leads to the formation of a carbocation:
- The carbocation is formed at the carbon that was attached to the hydroxyl group.
- The structure of the carbocation can be represented as:
```
CH₃
|
CH₃-C⁺-CH₃
|
H
```

### Step 4: Rearrangement of the carbocation
To stabilize the carbocation, a methyl group can shift from an adjacent carbon to the positively charged carbon, leading to a more stable tertiary carbocation:
- The rearrangement results in:
```
CH₃
|
CH₃-C-CH₃
|
CH₃
```

### Step 5: Elimination to form the alkene
The next step is the elimination of a proton (H⁺) from a beta-carbon to form the double bond, resulting in the formation of an alkene:
- The alkene formed will be:
```
CH₃
|
CH₃-C=CH₂
|
CH₃
```

### Step 6: Count the alpha-hydrogens
Alpha-hydrogens are the hydrogens attached to the carbon atoms adjacent to the double bond (alkene):
- In the alkene structure, we can see that:
- The carbon adjacent to the double bond has 3 alpha-hydrogens (from the CH₃ group).
- The other carbon adjacent to the double bond has 2 alpha-hydrogens (from the CH₂ group).

Thus, the total number of alpha-hydrogens in the product is:
- 3 (from one carbon) + 2 (from the other carbon) = 5 alpha-hydrogens.

### Final Answer
The number of alpha-hydrogen atoms in the product (alkene) formed is **5**.

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