`intsin^(-1)((2x)/(1+x^2))dx` is e q u a lto

intsin^-1x/(1-x^2)^(3/2)dx

intsin(tan^-1x)/(1+x^2)dx

int_(-1/(sqrt(3)))^(1/(sqrt(3)))(cos^(-1)((2x)/(x^2+1))+tan^(-1)((2x)/(1=x^2)))/(e^x+1)dxi se q u a lto int_(-pi/6)^(pi/6)(sec^2x)/(e^(tanx+1))dx (b) int_0^(pi/6)sec^2xdx pi/2int_(-pi/6)^(pi/6)(sec^2xdx)/(e^(tanx)+1) (d) pi/(2sqrt(3))

Evaluate: intsin^-1((2x)/(1+x^2))dx

intsin^(-1)(3x-4x^(3))dx=?

int(e^(2x)+(1)/(1+x^(2)))dx

Evaluate : (i) intsin^(-1)(3x-4x^(3))dx (ii) intsin^(-1)((2x)/(1+x^(2)))dx (iii) inttan^(-1)sqrt((1-x)/(1+x))dx (iv) intsin^(-1)sqrt((x)/(a+x))dx

intsin^(3)(2x+1)dx=?

int_(0)^(1)(e^(x))/(1+e^(2x))dx

intsin^2x/(1+cosx)^2dx