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Let 2x+ay+6z=8, x+2y+bz=5 and x+y+3z=4 b...

Let `2x+ay+6z=8, x+2y+bz=5 and x+y+3z=4` be three equations. If these 3 equations are consistent, then

A

`b=3, a ne 2`

B

`a=2, b ne 3`

C

`a ne 2, b ne 3`

D

`a ne 2, b = 4`

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The correct Answer is:
To determine the conditions under which the given system of equations is consistent, we will analyze the equations step by step. ### Given Equations: 1. \( 2x + ay + 6z = 8 \) (Equation 1) 2. \( x + 2y + bz = 5 \) (Equation 2) 3. \( x + y + 3z = 4 \) (Equation 3) ### Step 1: Write the Augmented Matrix We can express the system of equations in the form of an augmented matrix: \[ \begin{bmatrix} 2 & a & 6 & | & 8 \\ 1 & 2 & b & | & 5 \\ 1 & 1 & 3 & | & 4 \end{bmatrix} \] ### Step 2: Row Reduction to Echelon Form We will perform row operations to reduce this matrix to echelon form. 1. **R2 = R2 - (1/2)R1**: \[ R2 = \begin{bmatrix} 1 & 2 & b & | & 5 \end{bmatrix} - \frac{1}{2} \begin{bmatrix} 2 & a & 6 & | & 8 \end{bmatrix} \] This gives us: \[ R2 = \begin{bmatrix} 0 & 2 - \frac{a}{2} & b - 3 & | & 1 \end{bmatrix} \] 2. **R3 = R3 - (1/2)R1**: \[ R3 = \begin{bmatrix} 1 & 1 & 3 & | & 4 \end{bmatrix} - \frac{1}{2} \begin{bmatrix} 2 & a & 6 & | & 8 \end{bmatrix} \] This gives us: \[ R3 = \begin{bmatrix} 0 & 1 - \frac{a}{2} & 0 & | & 0 \end{bmatrix} \] Now the augmented matrix looks like this: \[ \begin{bmatrix} 2 & a & 6 & | & 8 \\ 0 & 2 - \frac{a}{2} & b - 3 & | & 1 \\ 0 & 1 - \frac{a}{2} & 0 & | & 0 \end{bmatrix} \] ### Step 3: Analyze Consistency For the system to be consistent, we need to analyze the conditions on \( a \) and \( b \). 1. **From Row 3**: The second column gives us \( 1 - \frac{a}{2} = 0 \) which implies \( a = 2 \). 2. **Substituting \( a = 2 \) into Row 2**: \[ R2 = \begin{bmatrix} 0 & 2 - 1 & b - 3 & | & 1 \end{bmatrix} \Rightarrow \begin{bmatrix} 0 & 1 & b - 3 & | & 1 \end{bmatrix} \] This leads to the equation: \[ (b - 3)z = 1 \] For this equation to hold true for some \( z \), we must have \( b - 3 \neq 0 \) (i.e., \( b \neq 3 \)). ### Conclusion Thus, the conditions for the system of equations to be consistent are: - \( a = 2 \) - \( b \neq 3 \) ### Final Answer The conditions for the equations to be consistent are: - \( a = 2 \) - \( b \neq 3 \)
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