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If p^("th"), 2p^("th") and 4p^("th") ter...

If `p^("th"), 2p^("th") and 4p^("th")` terms of an arithmetic progression are in geometric progression, then the common ratio of the geometric progression is

A

1

B

2

C

3

D

4

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The correct Answer is:
To solve the problem, we need to determine the common ratio of the geometric progression formed by the terms \( p^{th}, 2p^{th}, \) and \( 4p^{th} \) of an arithmetic progression. ### Step-by-Step Solution: 1. **Identify the Terms in AP**: Let the first term of the arithmetic progression (AP) be \( a \) and the common difference be \( d \). - The \( p^{th} \) term, \( T_p \), is given by: \[ T_p = a + (p - 1)d \] - The \( 2p^{th} \) term, \( T_{2p} \), is given by: \[ T_{2p} = a + (2p - 1)d \] - The \( 4p^{th} \) term, \( T_{4p} \), is given by: \[ T_{4p} = a + (4p - 1)d \] 2. **Condition for GP**: The terms \( T_p, T_{2p}, T_{4p} \) are in geometric progression (GP) if: \[ T_{2p}^2 = T_p \cdot T_{4p} \] 3. **Substituting the Terms**: Substitute the expressions for \( T_p, T_{2p}, T_{4p} \) into the GP condition: \[ (a + (2p - 1)d)^2 = (a + (p - 1)d)(a + (4p - 1)d) \] 4. **Expanding Both Sides**: - Left-hand side: \[ (a + (2p - 1)d)^2 = a^2 + 2a(2p - 1)d + (2p - 1)^2d^2 \] - Right-hand side: \[ (a + (p - 1)d)(a + (4p - 1)d = a^2 + (4p - 1 + p - 1)ad + (p - 1)(4p - 1)d^2 \] \[ = a^2 + (5p - 2)ad + (4p^2 - 5p + 1)d^2 \] 5. **Setting the Equations Equal**: Equate the left-hand side and right-hand side: \[ a^2 + 2a(2p - 1)d + (2p - 1)^2d^2 = a^2 + (5p - 2)ad + (4p^2 - 5p + 1)d^2 \] 6. **Cancelling \( a^2 \)**: Cancel \( a^2 \) from both sides: \[ 2a(2p - 1)d + (2p - 1)^2d^2 = (5p - 2)ad + (4p^2 - 5p + 1)d^2 \] 7. **Rearranging the Equation**: Rearranging gives: \[ (2(2p - 1) - (4p^2 - 5p + 1))d^2 + (2a(2p - 1) - (5p - 2))ad = 0 \] 8. **Finding the Common Ratio**: The common ratio \( r \) of the GP is given by: \[ r = \frac{T_{2p}}{T_p} = \frac{a + (2p - 1)d}{a + (p - 1)d} \] Substituting \( a = d \) (from earlier simplifications), we have: \[ r = \frac{d + (2p - 1)d}{d + (p - 1)d} = \frac{(2p)d}{(p)d} = 2 \] ### Conclusion: The common ratio of the geometric progression is \( \boxed{2} \).
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