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If A ={ theta : 2cos^2 theta + sintheta ...

If `A ={ theta : 2cos^2 theta + sintheta <=2}` , and `B = {theta: pi/2<=theta<= 3pi/2}` , then the region for `(AnnB)` is

A

`{theta:(pi)/(2)le theta le(5pi)/(6)}`

B

`{theta:pi le theta le(3pi)/(2)}`

C

`{theta: (pi)/(2) le theta le (5pi)/(6)} or {theta: pi le theta le (3pi)/(2)}`

D

`{theta:(3pi)/(4)le theta le (7pi)/(4)}`

Text Solution

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The correct Answer is:
C
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