In telophase I

Options

A. Nuclear envelop breaks down
B. The nuclear membrane separates the nuclear DNA from the cytoplasm
C. Each daughter cell has half the number of chromosomes
D. Both (b) and (c)

Answer

### Step-by-Step Solution:

1. **Understanding Telophase I in Meiosis**:
- Telophase I is the final stage of the first meiotic division. It follows Anaphase I, where homologous chromosomes have been separated and moved to opposite poles of the cell.

2. **Nuclear Envelope Formation**:
- During Telophase I, the nuclear envelope begins to reform around each set of separated chromosomes. This is a key feature of telophase, distinguishing it from earlier stages like prophase I.

3. **Cytokinesis**:
- Cytokinesis, the division of the cytoplasm, typically occurs during or immediately after telophase I. This results in the formation of two distinct daughter cells, each containing half the original number of chromosomes.

4. **Chromosome Number**:
- Each daughter cell at the end of Telophase I will have half the number of chromosomes compared to the original cell. This is because the homologous chromosomes have been separated, and each daughter cell receives one chromosome from each homologous pair.

5. **Final Outcome**:
- At the end of Telophase I, we have two cells that are haploid (n), meaning they contain one set of chromosomes. This is crucial for the subsequent stages of meiosis, where further division occurs.

### Conclusion:
- The correct statements regarding Telophase I in meiosis are:
1. The nuclear membrane separates the nuclear DNA from the cytoplasm.
2. Each daughter cell has half the number of chromosomes compared to the original cell.

Thus, the correct answer is that both statements 2 and 3 are true.